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andrezito [222]
3 years ago
8

ASAP

Chemistry
1 answer:
Solnce55 [7]3 years ago
5 0

Answer:

here's the answer to your question about

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If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?
laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

<em>where 1 mole of CaCl2 reacts with 2 moles of NaOH</em>

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

<em>Moles CaCl2 -Molar mass: 110.98g/mol-</em>

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

<em>Moles NaCl:</em>

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

<em>Mass NaCl -Molar mass: 58.44g/mol-</em>

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0
3 years ago
Are specimens the best source of DNA
xxTIMURxx [149]

no the best source is blood.

5 0
3 years ago
Precision Problems:
Lorico [155]

Answer:

Precision = 2.70 \± 0.1\ cm

Explanation:

Given

The data in the table

Required

Follow the steps appended to the question;

Step 1: Calculate the Mean or Average

Mean = Summation of lengths divided by number of teams;

Mean = \frac{2.65 + 2.75 + 2.80 + 2.77 + 2.60 + 2.65 + 2.68}{7}\ cm

Mean = \frac{18.9}{7}\ cm

Mean = 2.70\ cm

Step 2: Get The Range

Range = Highest - Lowest

Range = 2.80cm - 2.60cm

Range = 0.2\ cm

Step 3: Divide Range by 2

Approximate\ Range = \frac{1}{2}Range

Approximate\ Range = \frac{1}{2} * 0.2\ cm

Approximate\ Range = 0.1\ cm

Step 4: Determine the Precision

Precision = Average \± Approximate\ Range

Substitute 2.70 for Average and 0.1 for Approximate Range

Precision = 2.70 \± 0.1\ cm

4 0
3 years ago
What measurement of a liquid can you make with a graduated cylinder
Amanda [17]
Graduated cylinders have numbers on the side that help you determine the volume<span>.</span>
8 0
3 years ago
Read 2 more answers
What is the mass of KNO3(s) that must dissolve in 100. grams of water to form a saturated solution at 50.oC?
Ostrovityanka [42]
The solubility of substance depends upon the temperature. In present case, the solubility of KCl is 84g/100g at <span>50.oC. 

This means that, maximum 84g of KCl can be dissolved in 100g of water (at </span>50.oC) to form solution. This solution is referred as saturated solution. 

Thus, 84g of <span>KNO3 must be dissolve in 100 grams of water to form a saturated solution at 50 oC.</span>
4 0
4 years ago
Read 2 more answers
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