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Readme [11.4K]
4 years ago
5

2 pllllllslssssssssszssss

Chemistry
2 answers:
Masteriza [31]4 years ago
8 0
The answer is D glad to help :)<span />
Pepsi [2]4 years ago
8 0
A. Making food is the answer
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At what temperature will the following reaction happen spontaneously, given that ΔH = 8.91×103 J/mol and ΔS = –219.20 J/mol·K? C
Scrat [10]
In order for a certain reaction to be spontaneous, the change in Gibb's free energy must be negative, that is:
dG < 0

We can calculate dG using:
dG = dH - dS

When we plug in the given values, we see that the sign of dG will never be negative; therefore, the reaction will not be spontaneous under any conditions.
4 0
4 years ago
What is the empirical formula of a compound that has a pseudoformula of C3.5H8?
KIM [24]

Answer:

The ratio of carbon and hydrogen atoms = 3.5 : 8

= 7 : 16

Then,the empirical formula is C7H16

5 0
3 years ago
How many grams of lithium are in 3.50 moles of lithium
PolarNik [594]
Take the molar mass of lithium from your periodic table and multiply it by 3.5 moles
4 0
3 years ago
PLSSSSS HELP I DONT GET THIS PROBLEMMMM
Aleks [24]

Answer:

C. 7370 joules.

Explanation:

There is a mistake in the statement. Correct form is described below:

<em>Using the above data table and graph, calculate the total energy in Joules required to raise the temperature of 15 grams of ice at -5.00 °C to water at 35 °C. </em>

The total energy needed to raise the temperature is the combination of latent and sensible heats, all measured in joules, and represented by the following model:

Q = m\cdot [c_{i} \cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})] (1)

Where:

m - Mass of the sample, in grams.

c_{i} - Specific heat of ice, in joules per gram-degree Celsius.

c_{w} - Specific heat of water, in joules per gram-degree Celsius.

L_{f} - Latent heat of fusion, in joules per gram.

T_{1} - Initial temperature of the sample, in degrees Celsius.

T_{2} - Melting point of water, in degrees Celsius.

T_{3} - Final temperature of water, in degrees Celsius.

Q - Total energy, in joules.

If we know that m = 15\,g, c_{i} = 2.06\,\frac{J}{g\cdot ^{\circ}C}, c_{w} = 4.184\,\frac{J}{g\cdot ^{\circ}C}, L_{f} = 334.72\,\frac{J}{g}, T_{1} = -5\,^{\circ}C, T_{2} = 0\,^{\circ}C and T_{3} = 35\,^{\circ}C, then the final energy to raise the temperature of the sample is:

Q = (15\,g)\cdot \left[\left(2.06\,\frac{J}{g\cdot ^{\circ}C} \right)\cdot (5\,^{\circ}C)+ 334.72\,\frac{J}{g} + \left(4.184\,\frac{J}{g\cdot ^{\circ}C}\right)\cdot (35\,^{\circ}C) \right]

Q = 7371.9\,J

Hence, the correct answer is C.

8 0
3 years ago
What is the percent composition of CsF?
denis23 [38]

Answer:

Cs= 87.4931

F= 12.5069

Explanation:

7 0
3 years ago
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