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Flauer [41]
3 years ago
10

Help me and il give u brainlet or whatever they call it

Mathematics
2 answers:
Softa [21]3 years ago
7 0
1. If he drove at 55 mph he would drive 275 miles in 5 hours

2. If she buys 15 more she will spend $131.25 in total
HACTEHA [7]3 years ago
7 0

Answer:

1)He can drive 275miles 2)$26.25

Step-by-step explanation:

1) When you divide the amount of miles driven by the amount it took, you can find the mph Mr.Bell was driving at. 440/8=55, which means he drove at 55mph. In 5 hours, mr bell can drive 275miles when you multiply 55 by 5.

2)If you divide 105 (cost) by how many trays were purchased you can find how much costed per tray. 105/5=21. If it costs $21 per tray, you can divide how much a tray costs by how many plants are in it. 21/12=1.75. It costs $1.75 per plant. Multiplying 1.75 by how many additional plants are to be purchased, (15) you can find out how much it costs for their purchase. 1.75x15=26.25

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Denita has 4 coins. If Denita flips all the coins at once, how many outcomes are in the sample space?
Gennadij [26K]
There are 16 outcomes. You’d multiply the number of coins there are (4) by itself (4) and get 16.
4 0
4 years ago
Solve the system by graphing y=-2x + 2<br> y=-2x - 2
german

Answer:

<u>hope it helps...</u>

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6 0
3 years ago
0.2x + 0.8 = 9.6 find x<br><br> Please and thank you.
Akimi4 [234]

Answer:

x=44

Step-by-step explanation:

Making the equation in terms of x:

0.2x + 0.8 = 9.6

-0.8              -0.8

0.2x=8.8

*5      *5

x=44

8 0
3 years ago
Read 2 more answers
Solve using the zero product property x^2+11x+30=0 can you help please
skelet666 [1.2K]
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4 0
4 years ago
The average and standard deviation of a measurement is 15.0 ± 5.0. if 100 students measured the value, how many would you expect
AURORKA [14]

Solution: We are given:

\mu=15, \sigma=5

Using the empirical rule, we have:

\mu \pm \sigma covers 68% of data.

Also the percentage of values below mean = Percentage of values above mean = 50%

Now, let's find the z score for x=20

z=\frac{20-15}{5}=1

Therefore, the percentage of values greater than 1 standard deviation above mean 50\% - \frac{68\%}{2} =50\%-34\%=16%

Expected number of students = 16% of 100 = 16


4 0
4 years ago
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