Answer:
wu need help with
Step-by-step explanation:
that's easy it a
Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer:
y = -6x + 4
Step-by-step explanation:
2 parallel lines should have equal slope
Rewrite 6x + y = 92
It is now y = -6x + 92. Slope is -6
So the new equation should also have -6 as the slope.
y = -6x + b
Substitute (1,-2) into this equation
-2 = -6(1) + b
-2 = -6 + b
4 = b
So equation is y = -6x + 4
Answer:
3 1/3
Step-by-step explanation:
