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Effectus [21]
3 years ago
6

Why do you think football players are usually large in size?

Physics
2 answers:
kiruha [24]3 years ago
8 0
Football players in the NFL are large in size due to their eating habits since as players they have to work out constantly to stay and shape and eat to gain weight and be strong, so its important for them to be strong against their opponents in gameplay. Football players sometimes take steroids which make their muscles stronger and harder, and also gives them a growth spurt but the effects are worse and makes them sicker, high blood pressure, and even more. 
MA_775_DIABLO [31]3 years ago
5 0
I think practically all the football players you ever see are huge, because by the time you see them, they have already destroyed all the small ones.
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Do you have an image?


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3 years ago
A power company charges its customers for electricity based upon which one of the following?a. powerb. energyc. power per unit o
Vlad [161]

B. Energy

A power company charges its customers for electricity based upon B. Energy.

<h3>Explanation:</h3>

Kilo-watt Hours (kWh) is the unit that measures the electricity consumption of customers. Since Power is defined as the rate at which electrical energy is transferred by an electrical circuit per unit time,

P = \frac{E}{t} \\E= P\times t

If energy is transmitted at a constant rate over a period of time, the total energy in kilowatt hours is the product of power in kilowatts(kW) and time in hours (h)

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3 years ago
Rachel hits a golf ball into the air. What type of motion is the ball's path?
sladkih [1.3K]

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3 years ago
A 20 N south magnetic force pushes a charged particle traveling with a velocity of 4 m/s west through a 5 T magnetic field point
PtichkaEL [24]

Answer:

<u>Charge</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>particle</u><u> </u><u>is</u><u> </u><u>1</u><u> </u><u>coulomb</u><u>.</u>

Explanation:

Force, F:

{ \bf{F=BeV}}

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B is the magnetic flux density.

e is the charge of the particle.

V is the velocity

{ \sf{20 = (5 \times e \times 4)}} \\ { \sf{20e = 20}} \\ { \sf{e = 1 \: coulomb}}

8 0
3 years ago
The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak cu
Gemiola [76]

Answer:

6.66\cdot 10^{-12}T

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B=\frac{\mu_0 I}{2\pi r}

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In this problem we have

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So the magnetic field strength is

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5 0
3 years ago
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