What is a source of AC current

I have my exam monday I need some help!

Lana71 [14]

Answer:

Explanation:

If the passage of the waves is one crest every 2.5 seconds, then that is the frequency of the wave, f.

The distance between the 2 crests (or troughs) is the wavelength, λ.

We want the velocity of this wave. The equation that relates these 3 things is

$f=\frac{v}{\lambda}$ and filling in:

$2.5=\frac{v}{2.0}$ so

v = 2.5(2.0) and

v = 5.0 m/s

7 0

3 years ago

What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?

weeeeeb [17]

For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth

so here we can say

$F_g = \frac{mv^2}{r}$

$\frac{GMm}{r^2} = \frac{mv^2}{r}$

now we will have

$v = \sqrt{\frac{GM}{r}}$

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>

<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>

7 0

3 years ago

Which is the formula to calculate the slope of this line? A mass divided by volume B mass minus volume C volume divided by mass

Hatshy [7]

A- mass divided by volume

3 0

3 years ago

Three carts of masses 4.0 kg, 10kg, and 3.0 kg move on a frictionless track with speeds of v1 = 5.0m/s, v2=3.0m/s, and v3=-3.6 m

gogolik [260]

2.24 m/s is the calculated velocity.

Initial velocity (u) squared plus two times the acceleration (a) times the displacement equals final velocity (v) squared (s). Final velocity (v) is equal to the square root of initial velocity (u) squared plus two times the acceleration (a) times displacement when v is the variable being solved for (s).

The cart's masses and speeds are known.

M1 = 4.00 kg, M2 = 10.0 kg, M3 = 3.00 kg, etc.

v1 = 5.00 m/s = 5.00 m/s, v2 = 3.00 m/s = 3.00 m/s, v3 = -4.00 m/s = 4.00 m/s, and m1v1+m2v2+m3v3 = (m1+m2+m3) v=d frac m 1v 1+m 2v 2+m 3v 3, where (m1+m2 + m3) is the product of (v1 v 1+m2v2+m3v3).

"m 1+m 2+m 3" is equivalent to "m 1+m2+m3/m1v 1+m2v2 +m3v3"

the three carts' final velocities are calculated as follows: v=d frac

{4.00kg\sdot5.00m/s+10.0kg\sdot3.00m/s-3.00kg\sdot4.00m/s} 4.24m/s = 4.50kg+10.0kg+3.00kg vs. 4.50kg+10.0kg+3.00kg

5.00m/s/4.00kg/5.00m/s+10.0m/s/3.00m/s/4.00m/s =2.24m/s.

2.24 m/s is the calculated final velocity.

Learn more about velocity here-

brainly.com/question/18084516

#SPJ9

7 0

2 years ago

What is "In an isolated system two cars, each with a mass of 2,000 kg, collide. Car 1 is initially at rest , while car 2 was mov

yaroslaw [1]

Answer:

Final velocity of the combining cars = 10m/s

combined momentum = 40000kgm/s

Explanation:

Given the following :

Mass of both colliding cars = 2000kg

Initial Velocity of car 1 (U1) = 0

Initial Velocity of car 2 (U2) = 20m/s

Combuned momentum after collision =?

This is an inelastic collision which is calculated thus :

M1U1 + M2U2 = M1V + M2V

M1U1 + M2U2 = (M1 + M2) V

Where V = "final Velocity of the colliding bodies

2000 × 0 + 2000 × 20 = (2000 + 2000) V

0 + 40000 = 4000V

V = 40000 / 4000

V = 10m/s

Therefore combined momentum = (M1 + M2) V

(2000 + 2000) 10

4000(10) = 40000kgm/s

4 0

3 years ago