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torisob [31]
3 years ago
12

Sam is going on a spelunking trip and must cover 640 miles in 8 days. If Sam is spelunking 10 hours each day, how many miles mus

t he spelunk each hour?
Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer: 80

Step-by-step explanation: :D happy to help. Plz friend me!!!

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I need help. I'm confused ​
Alex
So, it is most likely that Joel runs 7 miles a day. On the x-axis would be the number of days he runs and the y-axis would be the mileage.
4 0
2 years ago
Given the diagram below, what is cos 45
Mamont248 [21]
Hey

Your answer is pretty simple

1/√2
Don't forget to mark Brainliest :^)
5 0
3 years ago
Find all the points, if any, where the graph of 12x-5y=0 intersects (x+12)^2+(y-5)^2=169.
WITCHER [35]
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169

with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0

insert into I:
12x=0
x=0

-> only intersection is at (0,0) = option B
6 0
3 years ago
Read 2 more answers
the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle
nikdorinn [45]
l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}
length\approx9.71cm;\ width\approx17.71cm
4 0
3 years ago
Solve c = ab? for b.
jek_recluse [69]

Answer:

b = c/a

Step-by-step explanation:

7 0
3 years ago
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