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navik [9.2K]
2 years ago
13

A simple pendulum with a length of 2 m oscillates on the Earth's surface. What is the period of oscillations?

Physics
1 answer:
stealth61 [152]2 years ago
5 0
What are the options?
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A 50 kg mass is placed 2 meters from the fulcrum. To balance the lever, a second object is placed 4 meters
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Answer:

mass =25 kg

using clockwise moment = anticlockwise moment

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Skin is the main barrier between internal organs and the outside environment. The outer layer of skin is composed mostly of epit
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In a recent experiment, anti-bacterial hand sanitizer was compared to hand soap. Students washed their hands using the sanitizer
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What's 600,000,000 divided by 3,000.000,000,000?
Murljashka [212]

Answer:0.000002

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5 0
3 years ago
A force of 10. N toward the right is exerted on a wooden crate initially moving to the right on a horizontal wooden floor. the c
Artyom0805 [142]

1) 5 N

The crate is initially moving, so we must calculate the force of kinetic friction, which is given by:

F_f = \mu_k mg

where

\mu_k=0.2 is the coefficient of friction between the crate (made of wood) and the floor (made of wood). The coefficient of kinetic friction between wood and wood is about 0.2.

mg=25 N is the weight of the crate

Substituting the numbers into the formula, we find

F_f=(0.2)(25 N)=5 N


2) 5 N

There are two forces acting on the crate along the horizontal direction:

- The force that pushes the crate toward the right, of magnitude F=10 N

- The force of friction, which acts in the opposite direction (so, towards the left), of magnitude F_f = 5 N

Since the two forces are in opposite directions, the net force is given by their difference:

F_{net}=F-F_f = 10 N-5 N=5 N


3) Yes

The crate is accelerating. In fact, according to Second Newton's Law:

F_{net}=ma (1)

where Fnet is the net force on the crate, m is its mass, a is its acceleration. We can immediately see that since Fnet is not zero, the acceleration is also non-zero, so the crate is accelerating.

We can even calculate the magnitude of the acceleration. In fact, the mass of the crate is given by:

m=\frac{Weight}{g}=\frac{25 N}{9.8 m/s^2}=2.55 kg

And by using (1) we find

a=\frac{F_{net}}{m}=\frac{5 N}{2.55 kg}=1.96 m/s^2


3 0
3 years ago
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