If the sun in 148 million kilometers from the earth, how many minutes will it take the light from the sun to reach the earth?

A very long string (linear density 0.7 kg/m ) is stretched with a tension of 70 N . One end of the string oscillates up and down

rewona [7]

To develop this problem it is necessary to apply the concepts related to Wavelength, The relationship between speed, voltage and linear density as well as frequency. By definition the speed as a function of the tension and the linear density is given by

$V = \sqrt{\frac{T}{\rho}}$

Where,

T = Tension

$\rho =$ Linear density

Our data are given by

Tension , T = 70 N

Linear density , $\rho = 0.7 kg/m$

Amplitude , A = 7 cm = 0.07 m

Period , t = 0.35 s

Replacing our values,

$V = \sqrt{\frac{T}{\rho}}$

$V = \sqrt{\frac{70}{0.7}$

$V = 10m/s$

Speed can also be expressed as

$V = \lambda f$

Re-arrange to find \lambda

$\lambda = \frac{V}{f}$

Where,

f = Frequency,

Which is also described in function of the Period as,

$f = \frac{1}{T}$

$f = \frac{1}{0.35}$

$f = 2.86 Hz$

Therefore replacing to find $\lambda$

$\lambda = \frac{10}{2.86}$

$\lambda = 3.49m$

Therefore the wavelength of the waves created in the string is 3.49m

3 0

3 years ago

A series of pulses, each of amplitude 0.1 m, is sent down a string that is attached to a post at one end. The pulses are reflect

AleksAgata [21]

Answer:

A_resulting = 0.2 m

Explanation:

Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.

With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is

A_res = 2A

A_resultant = 2 .01

A_resulting = 0.2 m

8 0

2 years ago

At an instant when a soccer ball is in contact with the foot of the player kicking it, the horizontal or x component of the ball

dedylja [7]

Answer:

Magnitude of net force will be 432.758 N

Explanation:

We have given x component of acceleration $a_x=760m/sec^2$

And vertical component of acceleration $a_y=770m/sec^2$

Mass of the ball m = 0.40 kg

So net acceleration $a=\sqrt{a_x^2+a_y^2}=\sqrt{760^2+770^2}=1081.896m/sec^2$

Now according to second law of motion

Force = mass × acceleration

So F = 0.40×1081.896 = 432.758 N

3 0

3 years ago

Which is an example of negative acceleration?

Sonja [21]

A graph that starts from the top left decreasing to the bottom right

4 0

3 years ago

Read 2 more answers

A student is wearing a pair of sunglasses designed to reduce the glare from reflected surfaces. When the student tilts her head

agasfer [191]

The answer is polarization. It is just like when you are on a boat and use polarized glasses so the water wont reflect into your eyes it also intensifies the color of the water so you can see better into the water.
example: you cant see any fish because glare from the sun, put on polarized glasses and now you can see fish up to 30 feet deep.

6 0

3 years ago