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Arada [10]
2 years ago
11

An object at rest will ______ unless acted upon by an unbalanced force.

Physics
2 answers:
Anvisha [2.4K]2 years ago
8 0

Answer:

remain at rest

Explanation:

An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

In the case of Newton's first law of motion: An object that is nonmoving remains at rest (unless acted upon by an unbalanced force); and a moving object will continue in its motion at a constant velocity (unless acted upon by an unbalanced force).

Hope this helps! =)

zvonat [6]2 years ago
4 0

Answer:

It's C because if you were trying to put it at rest that means you would put it on a Balanced surfest

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Answer:

Its the third law of motion.

Explanation:

Newton's third law of motion states that every action has equal and opposite reaction.

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Remember that the net force on you determines how your motion changes.  The strength of the gravitational force between two objects depends on two factors, mass and distance. The Mass of the Objects The more mass two objects have, the greater. the force of gravity the masses exert on each other.

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Metric conversions
sergij07 [2.7K]

1:-

  • 1L=1000mL

\\ \sf\longmapsto 45.23L

\\ \sf\longmapsto 45.23\times 1000

\\ \sf\longmapsto 45230mL

2:-

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\\ \sf\longmapsto .035hL

\\ \sf\longmapsto 0.035\times 10000

\\ \sf\longmapsto 350cL

3:-

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7 0
3 years ago
A 5.00 kg rock whose density is 4300 kg/m3 is suspended by a string such that half of the rock's volume is under water. You may
12345 [234]

Answer:

The tension on the string is  T  =  43.302 \ N

Explanation:

From the question we are told that

    The mass of the rock is m_r = 5.00 \ kg =  5000 \ g

       The density of the rock is \rho  =  4300 \ kg/m^3 =  4.3 g/dm^3

       

Generally the volume of the rock is mathematically evaluated as

          V    =  \frac{m_r}{\rho}

substituting values

        V    =  \frac{5000}{4.3}

       V    =  1162.7 \  dm^3

The volume of the rock immersed in water is

      V_w = \frac{V}{2}  

substituting values

     V_w = \frac{1162.7 }{2}

     V_w = 581.4 \ dm^3

mass of water been displaced by the this volume is

     m_w  = V_w     According to Archimedes principle

=>   m_w =  581.4 \ g

     m_w =  0.5814 \ kg

The weight of the water displace is  

      W _w =  m_w  * g

      W _w =  0.5814  * 9.8

      W _w = 5.698 \ N

The actual weight of the rock is  

      W_r  =  m_r * g

     W_r  =  5.0 *  9.8

     W_r  =  49.0 \ N

The tension on the string is

       T  = W_r - W_w

substituting values

       T  = 49.0 -  5.698

       T  =  43.302 \ N

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Is burning trash a physical change or chemical change?
astra-53 [7]
It's a chemical chemical change
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