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4 years ago

The wavelengths for visible light rays correspond to which of these options?

Physics

2 answers:

elena-s [515]4 years ago

6 0

Answer;

About the size of a virus or a large molecule

Explanation;

Visible light is a form of electromagnetic (EM) radiation, as are radio waves, infrared radiation, ultraviolet radiation, X-rays and microwaves. Generally, visible light is defined as the wavelengths that are visible to most human eyes.

Visible light falls in the range of the EM spectrum between infrared (IR) and ultraviolet (UV). It has frequencies of about 4 × 1014 to 8 × 1014 hertz (Hz) and wavelengths of about 740 nanometers (nm) to 380 nm .

The wavelength of visible light corresponds to the size of a virus or a large molecules which ranges from about 20 to 400 nanometres in diameter.

PilotLPTM [1.2K]4 years ago

6 0

The wavelengths for visible light rays correspond is about the size of a virus or a large molecule. Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

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You have a 160-Ω resistor and a 0.430-H inductor. Suppose you take the resistor and inductor and make a series circuit with a vo

S_A_V [24]

Answer:

A. Z = 185.87Ω

B. I = 0.16A

C. V = 1mV

D. VL = 68.8V

E. Ф = 30.59°

Explanation:

A. The impedance of a RL circuit is given by the following formula:

$Z=\sqrt{R^2+\omega^2L^2}$ (1)

R: resistance of the circuit = 160-Ω

w: angular frequency = 220 rad/s

L: inductance of the circuit = 0.430H

You replace in the equation (1):

$Z=\sqrt{(160\Omega)^2+(220rad/s)^2(0.430H)^2}=185.87\Omega$

The impedance of the circuit is 185.87Ω

B. The current amplitude is:

$I=\frac{V}{Z}$ (2)

V: voltage amplitude = 30.0V

$I=\frac{30.0V}{185.87\Omega}=0.16A$

The current amplitude is 0.16A

C. The current I is the same for each component of the circuit. Then, the voltage in the resistor is:

$V=\frac{I}{R}=\frac{0.16A}{160\Omega}=1*10^{-3}V=1mV$ (3)

D. The voltage across the inductor is:

$V_L=L\frac{dI}{dt}=L\frac{d(Icos(\omega t))}{dt}=-LIsin(\omega t)\\\\V_L=-(0.430H)(160\Omega)sin(220 t)=68.8sin(220t)\\\\V_L_{max}=68.8V$

E. The phase difference is given by:

$\phi=tan^{-1}(\frac{\omega L}{R})=tan^{-1}(\frac{(220rad/s)(0.430H)}{160\Omega})\\\\\phi=30.59\°$

5 0

3 years ago

Kinetic energy is energy that is stored and not moving<br> O True<br> O False

trasher [3.6K]

The answer to this is that it is FALSE!

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2 years ago

We have a metal plate that has a circular hole with radius "R". if we raise the temperature of this plate, what happened with ra

Sonbull [250]

If the metal plate that has a circular hole with radius R. And if we raise the temperature of this plate the radius of the hole will increase.

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3 years ago

djverab [1.8K]

Answer:

it converges to the focal point

Explanation:

6 0

3 years ago

How does the circuit change when the wire is added? a closed circuit occurs and makes all bulbs turn off. an open circuit occurs

Vitek1552 [10]

The circuit change when a wire is added is, an open circuit occurs and makes all bulbs turn off.

<h3>What is a closed circuit?</h3>

A closed circuit is a type of circuit connection in which the wire connection is complete and current flow occurs, turning the light bulbs on in the process.

<h3>What is an open circuit?</h3>

An open circuit is a type of circuit connection in which the wire connection is incomplete and current cannot flow, turning off the light bulbs.

Thus, the circuit change when the wire is added is, an open circuit occurs and makes all bulbs turn off.

Learn more about open circuit here: brainly.com/question/20351910

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3 0

2 years ago