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2 years ago

9

Please I don’t know how to do this

2 answers:

ivanzaharov [21]2 years ago

7 0

Answer:

Step-by-step explanation:

Hope this helps u!!

Andru [333]2 years ago

6 0

Answer:

somewhere on the y axis so ig -4,-2?

Step-by-step explanation:

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Helppp plsssss someone D:

zimovet [89]

〽Hola User_______________

⭐Here is Your Answer..!!!

______________________

↪Cartesian Coordinates of the system....!!

↪X = rcos⊙ and Y = rsin⊙

↪since here Radius (r) = 10 units and Theta (⊙) = 225°

↪there fore substituting we get as ..

↪X = 10 ( cos 225° ) = 10 * -1/ root 2 = -7.071

↪Y = 10 ( sin 225° ) = 10 * -1/root2 = = -7.071

↪the cordinates are as follows

↪(x,y) = (-7.071, -7.071 )

4 0

2 years ago

What is the value of the expression 8-(2to the 3rd Power+48)divided by 8

dalvyx [7]

8-(8+48) = -48 then divide that by 8 and you get -6 as your result

8 0

2 years ago

If y varies directly as x and y = 144 when x = 12, what is the value of y when x = 17?

olasank [31]

Direct variation:
$y=kx$

y=144 when x=12.
$144=12k \\ k=\frac{144}{12} \\ k=12$

y=? when x=17.
$y=12 \times 17 \\
y=204$

y=204 when x=17.

6 0

2 years ago

How can you tell from a table of values if a relationship is proportional?

dusya [7]

C- in the table every ratio y/x is equal so the relationship is proportional

4 0

2 years ago

Plllzzz im new and i neeed help

ella [17]

Answer:

4082

Step-by-step explanation:

Given

The composite object

Required

The volume

The object is a mix of a cone and a hemisphere

Such that:

<u>Cone</u>

$r = 10cm$ ---- radius (r = 20/2)

$h = 19cm$

<u>Hemisphere</u>

$r=10cm$

The volume of the cone is:

$V_1 = \frac{1}{3}\pi r^2h$

$V_1 = \frac{1}{3}\pi * 10^2 * 19$

$V_1 = \frac{1900}{3}\pi$

The volume of the hemisphere is:

$V_2 = \frac{2}{3}\pi r^3$

$V_2 = \frac{2}{3}\pi 10^3$

$V_2 = \frac{2000}{3}\pi$

So, the volume of the object is:

$V = V_1 + V_2$

$V = \frac{1900}{3}\pi + \frac{2000}{3}\pi$

$V = \frac{3900}{3}\pi$

$V = 1300\pi$

$V = 1300 * 3.14$

$V = 4082$

8 0

2 years ago