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photoshop1234 [79]
3 years ago
11

How are Newton’s Laws evident in everyday moving objects?

Chemistry
1 answer:
Basile [38]3 years ago
7 0

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

Explanation:

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Which of the following is a true statement about the water cycle?
Serggg [28]
I think its C: due to mixing and oceanic.....
3 0
3 years ago
The representative particles of a covalent compound is called
vichka [17]

Answer:

a molecule

Explanation:

 A molecule is the smallest unit quantity of a compound which can exist by itself and retain ALL the properties of the original substance.

Hope that helps

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5 0
2 years ago
fish give off the compound ammonia which has a pH above 7 to which class of compounds does ammonia belong
jasenka [17]
<span><u><em>Answer:</em></u>
The compound ammonia given by fish is alkaline

<u><em>Explanation:</em></u>
<u>We can classify elements/compounds based on their pH values into three types:</u>
<u>acids:</u> these are compounds having pH value lower than 7
<u>neutral:</u> these are compounds having pH value equal to 7
<u>alkalies:</u> these are compounds having pH values higher than 7

This is shown in the attached image

We are given that the pH of the compound ammonia generated by the fish is above 7.
According to the above explanation, compound ammonia would be an alkaline compound.

Hope this helps :)</span>

5 0
3 years ago
A sample of gas has a density of 0.53 g/L at 225 K and under a pressure of 108.8 kPa. Find the density of the gas at 345 K under
sukhopar [10]

Answer:

\rho _2=0.22g/L

Explanation:

Hello!

In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:

PV=nRT\\\\PV=\frac{m}{MM} RT\\\\P*MM=\frac{m}{V} RT\\\\P*MM=\rho RT

Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:

\frac{P_1*MM}{P_2*MM} =\frac{\rho _1RT_1}{\rho _2RT_2} \\\\\frac{P_1}{P_2} =\frac{\rho _1T_1}{\rho _2T_2}

It means we can compute the final density as shown below:

\rho _2=\frac{\rho _1T_1P_2}{P_1T_2}

Now, we plug in to obtain:

\rho _2=\frac{0.53g/L*225K*68.3kPa}{345K*108.8kPa}\\\\\rho _2=0.22g/L

Regards!

8 0
2 years ago
Imagine that you are playing a game of Clue in which Mrs. White is killed in the conservatory. You have a device in each room to
myrzilka [38]

Answer:

  • <u><em>Mr. Plum</em></u><em> killed Mrs. White.</em>

Explanation:

<u>1) Wavelengths for the different light colors (visible light) and related character:</u>

Color  Wavelength          related character

Violet  380–450 nm  ← Professr Plum

Blue  450–485 nm  ← Mrs. Peacock

Cyan  485–500 nm  

Green  500–565 nm  ← Mr. Green

Yellow  565–590 nm  ← Colonel Mustard

Orange  590–625 nm  

Red  625–740 nm  ← Miss Scarlet

<u>2) At the time of the murder, the spectrometers recorded:</u>

a) In the <em>dining room</em>: <em>520 nm</em>.

520 nm is in the range 500 - 565 nm, which is the range for green color, so <em>Mr. Green</em> was in the dining room and is no more a suspect.

b)<em> In the lounge and study: lower frequencie</em>s.

Since frequency and wavelength are inversely related, the wavelengths in the longe and study have to be of <em>yellow and red</em> colors, which are the only two with longer wavelengths from the option given.

Then, <em>Mustard and Scarlet</em> are not criminal.

c)<em> In the library: the second shortest wavelength of the five recorded. </em>

<em />

The second shortest wavelength, as per the table, is that of <em>blue </em>color. So, <em>Mrs. Peacock</em> is not the killer.

The only left option is violet, so Mr. Plum is the only who could be at the conservatory and he is the killer.

7 0
3 years ago
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