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photoshop1234 [79]
3 years ago
11

How are Newton’s Laws evident in everyday moving objects?

Chemistry
1 answer:
Basile [38]3 years ago
7 0

Answer:

Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.

Explanation:

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At 20 °C the vapor pressure of pure benzene (C6H6) is 75.0 torr, and that of toluene (C7H8) is 22.0 torr. Assume that benzene an
8090 [49]

Answer:

mole fraction benzene = 0.62

mole fraction toluene   = 0.38

Explanation:

Raoults law for ideal solutions tells us that the totoal vapor pressure of the solution will be given by adding the partial pressures of the components of  the solution and the partial pressures are simply given by the product of the component in solution times its pure vapor pressure at the temperature given:

<h2>p total = x₁  P⁰₁ + x₂  P⁰₂</h2>

where x1 and x2 for this solution denote the mole fractions of  benzene and toluene and p⁰ ₁, p⁰₂ the vapor pressures of benzene and toluene respectively.

Solving the algebraic equation:

75 x₁ + 22 x₂  = 55

75 x₁ + 22 ( 1- x₁) = 55   (since x₁ + x₂ = 1)

75 x₁ + 22 - 22 x₁ = 55

53 x₁  = 33

x₁ = 0.62  

x₂ = 1 - 0.62 = 0.38

6 0
3 years ago
What does the VSEPR theory describe?
sweet-ann [11.9K]

Answer: it is C, why molecules have different shapes.

Explanation:

A P E X

3 0
3 years ago
How do you calculate the number of neutrons in an atom? *
mrs_skeptik [129]

Answer: This means to find the number of neutrons you subtract the number of protons from the mass number.

7 0
3 years ago
Read 2 more answers
Balancing equations
Bad White [126]
Make sure you numbers with variable are on one side and the numbers 

7 0
4 years ago
If 10.0 liters of oxygen at STP are heated to 785.15 °K, what will be the new volume of gas if the pressure is also increased to
Ugo [173]

Answer: The new volume of gas is 28.5 L

Explanation:

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 1.00 atm (at STP)

P_2 = final pressure of gas = 102.6 kPa = 1.01 atm    (1 kPa= 0.0098 atm)

V_1 = initial volume of gas = 10.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 273.15K  (STP)

T_2 = final temperature of gas = 785.15K

Now put all the given values in the above equation, we get:

\frac{1.00\times 10.0}{273.15}=\frac{1.01\times V_2}{785.15}

V_2=28.5L

The new volume of gas is 28.5 L

8 0
3 years ago
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