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german
3 years ago
14

Which of the following is a true statement about the water cycle?

Chemistry
1 answer:
Serggg [28]3 years ago
3 0
I think its C: due to mixing and oceanic.....
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List the major points in daltons atomic theory
kvasek [131]
1. all elements are made of small particles called atoms
2. atoms of one element are identical in their properties, different atoms from different elements differ in properties
3. chemical reactions consist of atoms rearranging in whole number ratios
4. atoms can not be subdivided, created, or destroyed
5 0
4 years ago
Solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas. Express your answer as a chemical equa
Gwar [14]

Answer:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Explanation:

Hello!

In this case, when solid calcium carbonate, CaCO3 (s), is decomposed by the action of thermal energy (heat), solid calcium oxide, CaO (s) and carbon dioxide gas, CO2 (g) are yielded via the following reaction:

CaCO_3\rightarrow CaO+CO_2

However, since calcium carbonate is solid as well as calcium oxide and carbon dioxide is given off as a gas, we write:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

Which also balanced.

Best regards!

8 0
3 years ago
An naoh solution contains 1.90 mol of naoh, and its concentration is 0.555 m. what is its volume?
Firlakuza [10]
0.555 = 1.90/V
⇒ V = 1.90/0.555
⇒ V = 3.423 liter
6 0
3 years ago
identify what type of mixture powdered chalk and powdered table salt is and suggest a technique for separating their components
Iteru [2.4K]
This is a homogenous mixture because you cannot differentiate between the members of the mixture. A technique might be heating them until one melts and evaporates due to different boiling temperatures, or mixing them together with fluids that would dissolve one, yet keep the other one whole.
7 0
3 years ago
Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the vol
marta [7]

Answer:

V_2=19.23L

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

\frac{V_2}{n_2} =\frac{V_1}{n_1}

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol

Thus, we find:

V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L

Best regards.

6 0
3 years ago
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