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3 years ago

How many molecules are there in 10.5 grams of iron (111) sulfate trihydrate? With work shown

Chemistry

1 answer:

MrRa [10]3 years ago

8 0

Fe2(SO4)3.3H2O = 56*2 + 3*(32+16*4)+3*(1*2+16) = 454 g/mol
Mol =m/M = 10.5/454 = 0.023 mol
Can u mark it brainliest ?

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How many liters of oxygen are required to completely react with 2.0 liters of CH4 at30 °C and 3.0 atm?CH4(g) + 2O2(g) → CO2(g) +

Dominik [7]

1) Write the chemical equation.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

2) List the known and unknown quantities.

Sample: CH4.

Volume: 2.0 L.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Moles: unknown.

3) Moles of CH4.

3.1- Set the equation.

$PV=nRT$

3.2- Plug in the known values and solve for n (moles).

$(3.0\text{ }atm)(2.0\text{ }L)=n*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $n=\frac{(3.0\text{ }atm)(2.0\text{ }L)}{(0.082057\text{ }L*atm*K^{-1}*mol^{-1})}=$ $n=0.24\text{ }mol\text{ }CH_4$

4) Moles of oxygen that reacted.

The molar ratio between CH4 and O2 is 1 mol CH4: 2 mol O2.

$mol\text{ }O_2=0.24\text{ }CH_4*\frac{2\text{ }mol\text{ }O_2}{1\text{ }mol\text{ }CH_4}=0.48\text{ }mol\text{ }O_2$

5) Volume of oxygen required.

Sample: O2.

Moles: 0.48 mol.

Temperature: 30 ºC = 303.15 K.

Pressure: 3.0 atm.

Ideal gas constant: 0.082057 L * atm * K^(-1) * mol^(-1).

Volume: unknown.

5.1- Set the equation.

$PV=nRT$

5.2- Plug in the known values and solve for V (liters).

$(3.0\text{ }atm)(V)=0.48\text{ }O_2*(0.082057\text{ }L*atm*K^{-1}mol^{-1})(303.15\text{ }K)$ $V=\frac{(0.48\text{ }mol\text{ }O_2)(0.082057\text{ }L*atm*K^{-1}*mol^{-1})(303.15\text{ }K)}{3.0\text{ }atm}$ $V=3.98\text{ }L$

3.98 L of O2 is required to react with 2.0 L CH4.

6 0

2 years ago

A gas has a volume of 27.5 L at 302 K and 1.40 atm. How many moles are in the sample of gas?

ioda

Answer:

1.55 mol

Step-by-step explanation:

We can use the Ideal Gas Law to solve this problem.

pV = nRT Divide both sides by RT

n = (pV)/(RT)

Data:

p = 1.40 atm

V = 27.5 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 302 K

Calculations:

n = (1.40 × 27.5)/(0.082 06 × 302)

= 1.55 mol

6 0

3 years ago

Match the following terms and definitions.

KIM [24]

1 is accuracy
2. precision
3. bouyancy
4. mass
5. weight
6. density
7. specific gravity
8. volume

5 0

3 years ago

Read 2 more answers

What’s the molar mass of Lead-208

Degger [83]

Lead is a basic metal and almost 11 isotopes of Lead are reported. The isotopes with greater natural abundance are as follow;

1) ²⁰⁸Pb with abundance 52.4 %

2) ²⁰⁶Pb with abundance 24.1 %

3) ²⁰⁷Pb with abundance 22.1 %

4) ²⁰⁴Pb with abundance 1.4 %

Molar mass of ²⁰⁸Pb:

Molar mass of any element is the total of number of protons, neutrons and electrons.
As, number of protons in Lead are 82 then in ²⁰⁸Pb isotope number of neutrons are...

# of Neutrons = M.mass - # of protons

# of Neutrons = 208 - 82

# of Neutrons = 126

Result:

Molecular Mass of Lead (²⁰⁸Pb) is 208 amu.

# of Protons in ²⁰⁸Pb = 82

# of Neutrons in ²⁰⁸Pb = 126

7 0

4 years ago

Which of the following best describes the force causing a rocket to lift off?

Papessa [141]

B gravitational force

I took the test :)

3 0

3 years ago