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2 years ago

How many molecules are there in 10.5 grams of iron (111) sulfate trihydrate? With work shown

Chemistry

1 answer:

MrRa [10]2 years ago

8 0

Fe2(SO4)3.3H2O = 56*2 + 3*(32+16*4)+3*(1*2+16) = 454 g/mol
Mol =m/M = 10.5/454 = 0.023 mol
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What happens to the temperature of water when the average kinetic energy of its particles decreases

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2 years ago

4.3 moles of a gas are at a temperature of 28 degrees * C with a pressure of 1.631 atm. What volume does the gas occupy?

Shkiper50 [21]

Answer:

65.2L

Explanation:

Using the general gas equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (Litres)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (Kelvin)

According to the information provided in this question,

P = 1.631 atm

V = ?

n = 4.3 moles

T = 28°C = 28 + 273 = 301K

Using PV = nRT

V = nRT/P

V = 4.3 × 0.0821 × 301 ÷ 1.631

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V = 65.15

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2 years ago

Calculate the volume occupied by 272g

cupoosta [38]

The answer for the following problem is mentioned below.

Therefore volume occupied by methane gas is 184.78 × 10^-3 liters

Explanation:

Given:

mass of methane( $CH_{4}$ ) = 272 grams

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Also given:

R = 8.31JK-1 mol-1 ,

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We know;

According to the ideal gas equation,

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here,

n = m÷M

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n = 17 moles

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V = ( 17 × 8.31 × 327 ) ÷ ( 250×10^3 )

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Answer:

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