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kompoz [17]
3 years ago
15

How many molecules are there in 10.5 grams of iron (111) sulfate trihydrate? With work shown

Chemistry
1 answer:
MrRa [10]3 years ago
8 0
Fe2(SO4)3.3H2O = 56*2 + 3*(32+16*4)+3*(1*2+16) = 454 g/mol
Mol =m/M = 10.5/454 = 0.023 mol
Can u mark it brainliest ?
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igor_vitrenko [27]
The balanced equation for the above reaction is as follows;
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