Answer:
They will be 170 miles apart at 10 AM
Step-by-step explanation:
Nancy has 15´ of head start which is 1/4 hr.
NHD = 20*(1/4) = 5 miles is her head start
Mark leaves at 7.15hs = starting point
Marks stop at when they are 170 miles apart = t
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t = the time they are 170 miles apart
d= distance in miles Nancy travels in time t
170 - (d+5) = distance in miles Mark travels in time t
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Nancy's equation:
(1) d = 20t
Mark's equation:
(2) 170 - (d+5) = 40t
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(2) 170-d-5=40t
(2) d+40t=165
Substitute (1) into (2)
(2) 20t+40t=165
(2) 60t=165
(2) t=2.75
7:15 AM + 2.75 hrs (2:45hs) = 10 AM
They are 170 miles apart at 10 AM
check:
(1) d=20t
(1) d=20*2.75
(1) d=
55
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(2) 170 - (d+5) = 40t
(2) 170 - (d+5) = 40*2.75
(2) 170 - d-5 = 110
(2) d=55
Answer:
f(g(x))= x-2
Step-by-step explanation:
f(g(x))= (x-4)+2 -plug g(x) into the place of x in the f(x) function
f(g(x))= x-4+2 -parentheses aren't needed
f(g(x))=x-2 -combine like terms
Make a graph then point all of the number
So here is the solution to the given problem above.
Given that Serena drove 40km on 3L of gasoline, we can say that she drove 13.33 kilometers per liter of gasoline. Since we want to find out how far she travelled with a full tank of 50L, we will only multiply 13.33 by 50 and we get 666.67 kilometers. So the answer would be 666.67 kilometers for 50 L of gasoline. Hope this helps.
