1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STALIN [3.7K]
3 years ago
11

Question 4 Unsaved The names of all binary compounds, both ionic and molecular, end in the letters ____

Chemistry
2 answers:
EastWind [94]3 years ago
8 0

The answer to the question:

The names of all binary compounds, both ionic and molecular, end in the letters ____

Is:

-          ide

The names of all the binary compounds, both the molecular and ionic, end in the letters –ide.

ki77a [65]3 years ago
4 0
The answer is -ide for sure
You might be interested in
What are most conductors made of?<br><br> A: Wood<br> B: Paper<br> C: Plastic<br> D: Metal
mafiozo [28]

Answer:

D: Metal

Explanation:

Most conductors are made from metal, for the alloys allow for a "freer" passage way for electrons to pass through.

~

7 0
3 years ago
Read 2 more answers
Which Ions oxidize aluminum?<br><br> Li^+, Ca^2+, Ag+, Sn^2+
pishuonlain [190]

Aluminum can be oxidized by Li^{+} and Ca^{2+}

<h3>What is oxidizing?</h3>

Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.

According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)

Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.

Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.

∴ Li^{+} and Ca^{+2} ions can oxidize aluminum.

Learn more about electronegativity here brainly.com/question/16446391

#SPJ10

8 0
2 years ago
Given the following equation, N2O(g) + NO2(g) → 3 NO(g) ΔG°rxn = -23.0 kJ
Lelechka [254]

Answer:

ΔG°rxn = -69.0 kJ

Explanation:

Let's consider the following thermochemical equation.

N₂O(g) + NO₂(g) → 3 NO(g) ΔG°rxn = -23.0 kJ

Since ΔG°rxn < 0, this reaction is exergonic, that is, 23.0 kJ of energy are released. The Gibbs free energy is an extensive property, meaning that it depends on the amount of matter. Then, if we multiply the amount of matter by 3 (by multiplying the stoichiometric coefficients by 3), the ΔG°rxn will also be tripled.

3 N₂O(g) + 3 NO₂(g) → 9 NO(g) ΔG°rxn = -69.0 kJ

8 0
4 years ago
How many moles are in 124.7 g of Ba(OH)2
Alekssandra [29.7K]

Answer:

0.73 mol

Explanation:

No. of moles(n)= Given mass/molar mass.

Given mass=124.7g

Molar mass of Ba(OH)2= Molar mass of (Barium+2Oxygen+2Hydrogen)=137+32+2=171g

No. of moles= 124.7g/171g=0.73 mol

7 0
3 years ago
NO BOTS PLEASE HELP
Simora [160]

Answer:

C. 10.540 moles

Explanation:

divide grams by molar mass to get moles

8 0
2 years ago
Other questions:
  • How to do two step metric conversation​
    12·1 answer
  • Which of the following is an example of a homogeneous mixture?
    7·2 answers
  • decode the following message. using the atomic number plus the highest principle quantum number= 5, 30, 58, 56, 99, 79, 19, 98,
    6·1 answer
  • Which temperature scale would read the highest number for boiling water? A. Kelvin B. Celsius C. Fahrenheit
    6·2 answers
  • THIRTY POINTS I NEED HELP HURRY What is the volume of the cone?
    9·2 answers
  • I need help again guyss
    10·2 answers
  • For 20 points.... answer this
    13·2 answers
  • All of the following are solutions except?
    10·2 answers
  • Early scientists used microscopes and discovered that all living things are made of
    5·1 answer
  • The passage below describes an experiment. Read the passage and then follow the instructions below.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!