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oksian1 [2.3K]
2 years ago
10

NO BOTS PLEASE HELP

Chemistry
1 answer:
Simora [160]2 years ago
8 0

Answer:

C. 10.540 moles

Explanation:

divide grams by molar mass to get moles

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Rainforests may be located in what latitude range?
SpyIntel [72]

Answer:

near the equator where it's hot

6 0
3 years ago
If NaCl has a mass of 3.2g, what is the volume of chlorine gas at STP?
Shalnov [3]

Hey there!

Molar mass NaCl = 58.44 g/mol

58.44 g ----------------- 22.4 ( at STP )

3.2 g -------------------- Volume ??

Volume = ( 3.2 x 22.4 )  / 58.44

Volume = 71.68 / 58.44

Volume = 1.226 L

Hope this helps!

5 0
3 years ago
Read 2 more answers
An endothermic solution process is described by which of the following?
Temka [501]

Answer:

a. ΔΗ > 0, solution feels cold

Explanation:

Hello,

In this case, endothermic process are those in which we can find that the products have more energy than the reactants, therefore energy is absorbed, for which the following equation:

\Delta H=\Delta H_{products}-\Delta H_{reactants}

Must be greater than 0 (positive) thereby, for a solution process we find that the solution feels cold, in such a way, answer is a. ΔΗ > 0, solution feels cold.

Regards.

4 0
3 years ago
Which organelle is most responsible for whether a plant looks wilted or not?
Margaret [11]

Answer:

the nucleus

Explanation:

5 0
3 years ago
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What is the molality of a solution containing 5.0 moles of solute in 3.2 kg of solvent? Round to the nearest tenth. Don't forget
Alisiya [41]
The molality of the solution is a measure of its concentration that can be calculated by dividing the amount of substance in moles by the amount of the solvent in kilograms. Mathematically, this can be expressed as that of the equation below.
                              molality = amount of solute (mole) / amount of solvent (kg)
                              molality = 5 moles / 3.2 kg
                              molality = 1.5625 m
Rounding off the answer to the nearest tenths, will give the final answer of <em>1.6 m</em>. 
4 0
3 years ago
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