A. A pure chemical substance consisting of one type of atom
Answer:
-26.125 kj
Explanation:
Given data:
Mass of water = 250.0 g
Initial temperature = 30.0°C
Final temperature = 5.0°C
Amount of energy lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 5.0°C - 30.0°C
ΔT = -25°C
Specific heat of water is 4.18 j/g.°C
Now we will put the values in formula.
Q = m.c. ΔT
Q = 250.0 g × 4.18 j/g.°C × -25°C
Q = -26125 j
J to kJ
-26125 j ×1 kj /1000 j
-26.125 kj
When MgO and H2O react they form Magnesium Hydroxide Mg(OH)2
Answer:
2.08L
Explanation:
V1 = 2.00L
P1 = 101kPa
P2 = 97.0kPa
V2 = ?
from Boyle's law,
P1V1 = P2V2
101 × 2 = 97 × V2
V2 = 202/97 = 2.08L
Therefore, the new volume is 2.08L
Answer:
Some scientists hypothesize that Earth's ozone layer is being damaged by chlorofluorocarbons .
Explanation:
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