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suter [353]
3 years ago
14

Calculate 1.23 m x 0.89 m and give your answer with the correct number of significant figures?

Chemistry
1 answer:
Marizza181 [45]3 years ago
4 0

Answer:

1.1m that what I got and it said it was right

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D) reacts with oxygen
All other are physical properties.
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What atomic component contributes to many of the trends of elements
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Which law relates to the ideal gas law?
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<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

There are 4 laws of gases:

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Mathematically,

P_1V_1=P_2V_2

  • <u>Charles' Law:</u> This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

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\frac{V_1}{T_1}=\frac{V_2}{T_2}

  • <u>Gay-Lussac Law:</u> This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

  • <u>Avogadro's Law:</u> This law states that volume is directly proportional to number of moles at constant temperature and pressure.

Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

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When calcium carbonate reacts with hydrochloric acid, calcium ions are transferred to the solution. Write only one net ionic equ
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In conclusion, the net ionic equation for the reaction between calcium carbonate and hydrochloric acid is CaCO3 solid plus two H+ aqueous react to form Ca2+ aqueous plus CO2 gas plus H2O liquid.

6 0
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Part b an "empty" container is not really empty if it contains air. how may moles of nitrogen are in an "empty" two-liter cola b
Sedbober [7]
<span>6.38x10^-2 moles
       First, let's determine how many moles of gas particles are in the two-liter container. The molar volume for 1 mole at 25C and 1 atmosphere is 24.465 liters/mole. So
   2 L / 24.465 L/mol = 0.081749438 mol
       Now air doesn't just consist of nitrogen. It also has oxygen, carbon dioxide, argon, water vapor, etc. and the total number of moles includes all of those other gasses. So let's multiply by the percentage of nitrogen in the atmosphere which is 78%
    0.081749438 mol * 0.78 = 0.063764562 mol.
        Rounding to 3 significant figures gives 6.38x10^-2 moles</span>
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