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Mashutka [201]
3 years ago
7

A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit

hin a cylinder. If the original pressure was 1.00 atm, the final pressure be _ atm. Answer in 3 sig figs.
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

The answer to your question is   P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K                 Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L                             Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1                                  Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

                          P1V1/T1 = P2V2/T2

-Solve for P2

                           P2 = P1V1T2 / T1V2

-Substitution

                          P2 = (1)(24)(298) / (263)(35)

-Simplification

                          P2 = 7152 / 9205

-Result

                          P2 = 0.777

   or                    P2 = 0.78 atm

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7.3 g (NH₄)₃PO₄

Explanation:

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To find the mass of ammonium phosphate ((NH₄)₃PO₄) produced, you need to (1) convert grams NH₃ to moles NH₃ (via the molar mass from the periodic table), then (2) convert moles NH₃ to moles (NH₄)₃PO₄ (via mole-to-mole ratio from balanced equation), and then (3) convert moles (NH₄)₃PO₄ to grams (NH₄)₃PO₄ (via molar mass from periodic table). Make sure to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 2 sig figs because the given value (2.5 grams) has 2 sig figs.

Molar Mass (NH₃): 14.01 g/mol + 3(1.008 g/mol)

Molar Mass (NH₃): 17.034 g/mol

Molar Mass ((NH₄)₃PO₄):

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Molar Mass ((NH₄)₃PO₄): 149.096 g/mol

2.5 g NH₃          1 mole NH₃        1 mole (NH₄)₃PO₄             149.096 g
---------------  x  --------------------  x  ---------------------------  x  --------------------------
                            17.034 g             3 moles NH₃              1 mole (NH₄)₃PO₄

=  7.3 g (NH₄)₃PO₄

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