Answer:it’s C
Explanation:
I just got it wrong and it showed the the right answer
 
        
             
        
        
        
<h2>
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h2>
<em>The female part is the pistil. The pistil usually is located in the center of the flower and is made up of three parts: the stigma, style, and ovary. The stigma is the sticky knob at the top of the pistil. It is attached to the long, tube</em><em> </em><em>like structure called the style</em><em>.</em>
<h3>
<em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>I</u></em><em><u>t</u></em><em><u> </u></em><em><u>W</u></em><em><u>i</u></em><em><u>l</u></em><em><u>l</u></em><em><u> </u></em><em><u>H</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u> </u></em><em><u>Y</u></em><em><u>o</u></em><em><u>u</u></em><em><u> </u></em><em><u>!</u></em></h3>
 
        
        
        
Answer : The equilibrium concentration of  at
 at  is,
 is,  .
.
Solution : Given,
Equilibrium constant, 
Initial concentration of  = 0.260 m
 = 0.260 m
Let, the 'x' mol/L of  are formed and at same time 'x' mol/L of
 are formed and at same time 'x' mol/L of  are also formed.
 are also formed.
The equilibrium reaction is,
                   
Initially                0.260 m                       0                 0
At equilibrium    (0.260 - x)                     x                 x
The expression for equilibrium constant for a given reaction is,
![K_c=\frac{[H_3O^+][C_2H_3O_2^-]}{[HC_2H_3O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BC_2H_3O_2%5E-%5D%7D%7B%5BHC_2H_3O_2%5D%7D)
Now put all the given values in this expression, we get

By rearranging the terms, we get the value of 'x'.

Therefore, the equilibrium concentration of  at
 at  is,
 is,  .
.