I got B. Because the answer is K2SO4, I got it right on my test so I know its right
Answer:
The 2 would be placed in front of the reactant Na and in front of the product NaCl
2Na + Cl2 = 2NaCl
Explanation:
This is because the ratio of elements needs to be balanced on both sides.
On the reactants side, there are 2 Na molecules and 2 Cl molecules
On the products side, there are 2 Na molecules and 2 Cl molecules
So, now the equation is balanced
430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
<h3>What is Molarity?</h3>
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>
Remember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
Learn more about Molarity here:
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1.64 L of sulfur dioxide (SO₂)
Explanation:
We have the following chemical reaction:
S (s) + O₂ (g) → SO₂ (g)
First we calculate the number of moles of sulfur (S):
number of moles = mass / molar weight
number of moles of sulfur = 2.35 / 32 = 0.0734 moles
Looking at the chemical reaction we see that 1 moles of sulfur (S) produces 1 moles of sulfur dioxide (SO₂), so 0.0734 moles of sulfur will produce 0.0734 moles of sulfur dioxide (SO₂).
To calculate the volume of sulfur dioxide (SO₂), assuming that the sulfur dioxide is behaving as an ideal gas and the we determine the gas volume under standard temperature and pressure conditions, we use the following formula:
number of moles = volume / 22.4 (L/mole)
volume = number of moles × 22.4
volume of SO₂ = 0.0734 × 22.4 = 1.64 L
Learn more about:
molar volume
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PS: I appreciate that you took the time and effort to write the chemical equation in a readable way. This makes the question to be very rare :D
