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Gwar [14]
3 years ago
11

The buildup of plaque on the walls of an artery may decrease its diameter from 1.1cm to 0.75 cm. If the speed of blood flow is 1

5 cm/s, before reaching the region of plaque buildup, find the speed (in cm/s) of the blood flow. [Express the answer in ONE decimal place]
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

v₂ = 32.4 cm/s

Explanation:

From the continuity equation it is clear that:

Volume Flow Rate Before Plaque = Volume Flow Rate In Plaque

Q₁ = Q₂

A₁v₁ = A₂v₂

where,

A₁ = Area of artery before plaque build up = πd²/4 = π(1.1 cm)²/4 = 0.95 cm²

A₂ = Area of artery with plaque build up = πd²/4 = π(0.75 cm)²/4 = 0.44 cm²

v₁ = velocity of blood flow in artery before plaque region = 15 cm/s

v₂ = velocity of blood in artery in plaque region = ?

Therefore,

(0.95 cm²)(15 cm/s) = (0.44 cm²)(v₂)

v₂ = (14.25 cm³/s)/(0.44 cm²)

<u>v₂ = 32.4 cm/s</u>

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(Sorry I could not assume with the values you gave, they are wrong, and if we use them we would be insulting Physics).


So F = ((6.67 * 10 ^ -11)*(5.97 x 10^24)*(7.34 * 10^22)) / (3.8 x 10^8)^2.
  Punch it all up in your calculator.
 
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F = 2.0240 * 10^ 20 N.
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