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Gwar [14]
3 years ago
11

The buildup of plaque on the walls of an artery may decrease its diameter from 1.1cm to 0.75 cm. If the speed of blood flow is 1

5 cm/s, before reaching the region of plaque buildup, find the speed (in cm/s) of the blood flow. [Express the answer in ONE decimal place]
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

v₂ = 32.4 cm/s

Explanation:

From the continuity equation it is clear that:

Volume Flow Rate Before Plaque = Volume Flow Rate In Plaque

Q₁ = Q₂

A₁v₁ = A₂v₂

where,

A₁ = Area of artery before plaque build up = πd²/4 = π(1.1 cm)²/4 = 0.95 cm²

A₂ = Area of artery with plaque build up = πd²/4 = π(0.75 cm)²/4 = 0.44 cm²

v₁ = velocity of blood flow in artery before plaque region = 15 cm/s

v₂ = velocity of blood in artery in plaque region = ?

Therefore,

(0.95 cm²)(15 cm/s) = (0.44 cm²)(v₂)

v₂ = (14.25 cm³/s)/(0.44 cm²)

<u>v₂ = 32.4 cm/s</u>

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8 0
3 years ago
A river flows due south with a speed of 2.0 m/s. You steer a motorboat across the river; your velocity relative to the water is
neonofarm [45]

Answer:

a) 25.5°(south of east)

b) 119 s

c) 238 m

Explanation:

solution:

we have river speed v_{r}=2 m/s

velocity of motorboat relative to water is v_{m/r}=4.2 m/s

so speed will be:

a) v_{m}=v_{r}+v_{m/r}

solving graphically

v_{m}=\sqrt{v^2_{r}+v^2_{m/r}}

     =4.7 m/s

Ф=tan^{-1} (\frac{v_{r}}{v_{m/r}} )

  =25.5°(south of east)

b) time to cross the river: t=\frac{w}{v_{m/r}}=\frac{500}{4.2}=119 s

c) d=v_{r}t=(2)(119)=238 m

note :

pic is attached

6 0
3 years ago
A potential energy function is given by u(x)=(3.00n)xâ(1.00n/m2)x3. at what position or positions is the force equal to zero?
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I believe the correct form of the energy function is:

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or in simpler terms without the units:

u (x) = 3 x + x^3

Since the highest degree is power of 3, therefore there are two roots or solutions of the equation.

 

Since we are to find for the positions x in which the force equal to zero, u (x) = 0, therefore:

3 x + x^3 = u (x)

3 x + x^3 = 0

Taking out x:

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So one of the factors is x = 0.

 

Finding for the other two factors, we divide the two sides by x and giving us:

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The other two roots are imaginary therefore the force is only equal to zero when the position is also zero.

 

Answer:

x = 0

5 0
3 years ago
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