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Gwar [14]
3 years ago
11

The buildup of plaque on the walls of an artery may decrease its diameter from 1.1cm to 0.75 cm. If the speed of blood flow is 1

5 cm/s, before reaching the region of plaque buildup, find the speed (in cm/s) of the blood flow. [Express the answer in ONE decimal place]
Physics
1 answer:
34kurt3 years ago
3 0

Answer:

v₂ = 32.4 cm/s

Explanation:

From the continuity equation it is clear that:

Volume Flow Rate Before Plaque = Volume Flow Rate In Plaque

Q₁ = Q₂

A₁v₁ = A₂v₂

where,

A₁ = Area of artery before plaque build up = πd²/4 = π(1.1 cm)²/4 = 0.95 cm²

A₂ = Area of artery with plaque build up = πd²/4 = π(0.75 cm)²/4 = 0.44 cm²

v₁ = velocity of blood flow in artery before plaque region = 15 cm/s

v₂ = velocity of blood in artery in plaque region = ?

Therefore,

(0.95 cm²)(15 cm/s) = (0.44 cm²)(v₂)

v₂ = (14.25 cm³/s)/(0.44 cm²)

<u>v₂ = 32.4 cm/s</u>

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What would we need to do to make an electromagnet strong enough to move cars and trains
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Answer:

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5 0
2 years ago
Suppose a wheel with a tire mounted on it is rotating at the constant rate of 3.33 times a second. A tack is stuck in the tire a
Troyanec [42]

Answer: 6.47m/s

Explanation:

The tangential speed can be defined in terms of linear speed. The linear speed is the distance traveled with respect to time taken. The tangential speed is basically, the linear speed across a circular path.

The time taken for 1 revolution is, 1/3.33 = 0.30s

velocity of the wheel = d/t

Since d is not given, we find d by using formula for the circumference of a circle. 2πr. Thus, V = 2πr/t

V = 2π * 0.309 / 0.3

V = 1.94/0.3

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The tangential speed of the tack is 6.47m/s

7 0
3 years ago
Read 2 more answers
A racquetball strikes a wall with a speed of 30 m/s and rebounds in the opposite direction with a speed of 26 m/s. The collision
Fudgin [204]

Answer:

The average acceleration of the ball during the collision with the wall is a=2,800m/s^{2}

Explanation:

<u>Known Data</u>

We will asume initial speed has a negative direction, v_{i}=-30m/s, final speed has a positive direction, v_{f}=26m/s, \Delta t=20ms=0.020s and mass m_{b}.

<u>Initial momentum</u>

p_{i}=mv_{i}=(-30m/s)(m_{b})=-30m_{b}\ m/s

<u>final momentum</u>

p_{f}=mv_{f}=(26m/s)(m_{b})=26m_{b}\ m/s

<u>Impulse</u>

I=\Delta p=p_{f}-p_{i}=26m_{b}\ m/s-(-30m_{b}\ m/s)=56m_{b}\ m/s

<u>Average Force</u>

F=\frac{\Delta p}{\Delta t} =\frac{56m_{b}\ m/s}{0.020s} =2800m_{b} \ m/s^{2}

<u>Average acceleration</u>

F=ma, so a=\frac{F}{m_{b}}.

Therefore, a=\frac{2800m_{b} \ m/s^{2}}{m_{b}} =2800m/s^{2}

8 0
3 years ago
Light from a 560 nm monochromatic source is incident upon the surface of fused quartz (n=1. 56) at an angle of 60°. what is the
ankoles [38]

The angle of reflection is "60°".

Here we apply the law of the concept of reflection then we get the final answer easily.

The angle of incident = angle of reflection

Then, the Angle of the incident =60°

What is reflection?

  • Reflection is the phenomenon of light rays returning to the source after striking an obstruction.
  • It resembles the way a ball bounces when we toss it on a hard surface.
  • Some of the light rays that strike an item are reflected, some of them travel through it, and the remainder are absorbed by the object.
  • The given values are:Light from a monochromatic source,= 560 nm
  • The angle of incidence,= 60°
  • The surface of fused quartz (n),= 1.56
  • When a light ray does exist on a flat surface, the law or idea of reflection should apply since it includes both the reflected and "normal" light rays at the mirror surface.
  • According to the above law,Angle of incident = angle of reflection
  • Then, Angle of incident =60°.

To learn more about reflection visit: brainly.com/question/15487308

#SPJ4

7 0
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