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Citrus2011 [14]
3 years ago
7

Determine the values of m and n when the following average distance from the Sun to the Earth is written in scientific notation:

150,000,000,000 m.
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

150000000000\ m=1.5\times 10^{11}\ m

Explanation:

A number can be written in the form of :

N=m\times 10^n

Where

m is the real number

n is any integer

In this case, the average distance from the Sun to the Earth is given,

d = 150000000000 meters

There are 10 zeroes in this number. We need to write this number in scientific notation. It is given by :

d=1.5\times 10^{11}\ m

So, the average distance from the Sun to the Earth is d=1.5\times 10^{11}\ m. Hence, this is the required solution.

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A bike rider does work to get to the top of a mountain. How could you use the law of conservation of energy to describe his trip
netineya [11]
The correct answer is (a.) The rider uses energy to do work going up the mountain. As the law of conservation of energy states that the total energy must be constant, therefore, the energy that is used to go up will be as it is to go down.
5 0
3 years ago
A car's acceleration is 3m/s2. If the car started at rest and it only took 10s for the car to reach this acceleration, what is t
Grace [21]

Answer:

30m/s

Explanation:

From law of motion equation

Vf= Vi + at

Where Vf= final velocity

Vi= initial velocity=0(the car started at rest)

a= acceleration= 3m/s2

t= time= 10s

Then substitute into the equation to get the final velocity.

Vf= 0+(10×3)

Vf= 30m/s

Hence, the car's final velocity is 30m/s

5 0
3 years ago
help me.. a car moves for half of its time at 80km/h nd for rest of time at 40km/h.total distance coverd is 60km..wat is averge
nalin [4]
Let's use ' t ' to represent half of the time, in hours.

The distance traveled in the first half of the time is  (80 t) km.

The distance traveled in the last half of the time is  (40 t) km.

The total distance covered is    (80t + 40t) = (120t)  km.

You said that the total distance covered was  60 km,
so ...
                             120 t  =  60 km

Divide each side by  120 :      t (half of the time) = 0.5 hour

Average speed = (total distance covered) / (time to cover the distance)

                           =      (60 km)  /  (1 hour)

                           =            60 km/hr .
5 0
3 years ago
A 286-kg motorcycle is accelerating up along a ramp that is inclined 31.6° above the horizontal. The propulsion force pushing th
kkurt [141]

Answer:

The acceleration motorcycle

a = 5.13 m / s²

Explanation:

Now to determine the acceleration of the motorcycle

Use the force to analysis motion

∑ F = m * a

∑ F = E - D - m*g * sin ( β ) = m * a

E = 3168 N

D = 230 N

β = 31.6 °

3168 N - 230 N - 286 kg * 9.8 m / s² * sin ( 31.6° ) = 286 kg * a

Now solve to a'

a = [ 3168 N - 230 N - 286 kg * 9.8  m / s² * sin ( 31.6° ) ] / (286 kg)

a = 5.13 m / s²

7 0
3 years ago
A 3.2-kg thin, circular hoop with a radius of 5.4 m is rotating about an axis through its center and perpendicular to its plane.
elena-14-01-66 [18.8K]

Answer:

Torque = –207.4 Nm

Explanation:

Given M = 3.2kg, r = 5.4m, α = –12rad/s² (it is slowing down)

Torque = I × α

α = angular acceleration

I = moment of inertia

I = MR² for a circular hoop

Torque = 3.2×5.4×(– 12)

Torque = –207.4 Nm

6 0
3 years ago
Read 2 more answers
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