Answer:
All 3 are CSS unit sizes which we can use for margins, fonts, borders etc.
Exp
CSS has four different unit sizes. These are:
Pixels (px)
Points (pt)
Ems (em)
Percentages(%)
These units are divided into two different groups. They are fixed and relative.
Pixels and points are fixed , whereas em and percentages are relative unit sizes. Relative unit sizes are good when creating scalable layouts.
Ems (em):
An em is a CSS unit that measures the size of a font. Originally, the em was equal to the width of the capital letter M, which is where its name originated.
It stands for "emphemeral unit" which is relative to the current font size.
The "em" is a scalable unit that is used in web document media. Ems have mobile-device-friendly nature.
Pixels (px):
Pixels are fixed-size units that are used in screen media. One pixel is equal to one dot in computer. The problem with pixel unit is that it is not relative .
Points (pt):
Point values are only for print. A point is a unit of measurement use for real-life ink on paper. Generally, 72pts= 1 inch which is one real-life inch like on a ruler. Point is not recommended to use in web pages.
Generally, 1em=16px=12pt=100% if the body size is 100%.
Relative unit sized fonts change and fixed unit sized fonts remain the same.
For example,
body { font-size: 100%}
p{font-size: 16px}
Question is not complete and the missing part is;
A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center. The disk rotates at a constant rate in a counterclockwise direction. The coin does not slip, and the time it takes for the coin to make a complete revolution is 1.5 s.
Answer:
0.828 m/s
Explanation:
Resolving vertically, we have;
Fn and Fg act vertically. Thus,
Fn - Fg = 0 - - - - eq(1)
Resolving horizontally, we have;
Ff = ma - - - - eq(2)
Now, Fn and Fg are both mg and both will cancel out in eq 1.
Leaving us with eq 2.
So, Ff = ma
Now, Frictional force: Ff = μmg where μ is coefficient of friction.
Also, a = v²/r
Where v is linear speed or velocity
Thus,
μmg = mv²/r
m will cancel out,
Thus, μg = v²/r
Making v the subject;
rμg = v²
v = √rμg
Plugging in the relevant values,
v = √0.14 x 0.5 x 9.8
v = √0.686
v = 0.828 m/s
To find velocity at a given moment, also known as instantaneous velocity, we need to know how to take the derivative of an equation;
you can take the derivative of s(t)=62t^2+ 375 by first moving the 2 in front of 162 and multiply both which well give you 324t and 375 will turn to 0
-16t^2 results in -32t
so our velocity at t=4 is -32(4) = -128ft per second
Answer:
47.5 m/s
Explanation:
Given:
Δy = -24.0 m
v = -42.3 m/s
a = -9.8 m/s²
Find: v₀
v² = v₀² + 2aΔy
v² = (-42.3 m/s)² + 2 (-9.8 m/s²) (-24.0 m)
v = 47.5 m/s
Answer:
C. 352.0 kg-m/s
Explanation: Took the test on APEX