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Citrus2011 [14]
3 years ago
7

Determine the values of m and n when the following average distance from the Sun to the Earth is written in scientific notation:

150,000,000,000 m.
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Answer:

150000000000\ m=1.5\times 10^{11}\ m

Explanation:

A number can be written in the form of :

N=m\times 10^n

Where

m is the real number

n is any integer

In this case, the average distance from the Sun to the Earth is given,

d = 150000000000 meters

There are 10 zeroes in this number. We need to write this number in scientific notation. It is given by :

d=1.5\times 10^{11}\ m

So, the average distance from the Sun to the Earth is d=1.5\times 10^{11}\ m. Hence, this is the required solution.

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The number of mushrooms needed by a pizza restaurant is given by the
kupik [55]

Answer: 24

Explanation:

Given the following equation:

g=3n

Where g is the number of mushrooms in a pizza and n the number of pizzas.

If we know the restaurant will make 8 pizzas (n=8), then:

g=3(8)

g=24 This is the needed number of mushrooms for 8 pizzas

8 0
3 years ago
Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
Katena32 [7]

Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

7 0
3 years ago
You have a pulley 10.4 cm in diameter and with a mass of 2.3 kg. You get to wondering whether the pulley is uniform. That is, is
madreJ [45]

Answer:

Explanation:

Given

Diameter of Pulley=10.4 cm

mass of Pulley(m)=2.3 kg

mass of book(m_0)=1.7 kg

height(h)=1 m

time taken=0.64 s

h=ut+frac{at^2}{2}

1=0+\frac{a(0.64)^2}{2}

a=4.88 m/s^2and [tex]a=\alpha r

where \alphais angular acceleration of pulley

4.88=\alpha \times 5.2\times 10^{-2}

\alpha =93.84 rad/s^2

And Tension in Rope

T=m(g-a)

T=1.7\times (9.8-4.88)

T=8.364 N

and Tension will provide Torque

T\times r=I\cdot \alpha

8.364\times 5.2\times 10^{-2}=I\times 93.84

I=0.463\times 10^{-2} kg-m^2

I_{original}=\frac{mr^2}{2}=0.31\times 10^{-2}kg-m^2

Thus mass is uniformly distributed or some more towards periphery of Pulley

4 0
3 years ago
Lifting a box off the floor is an example of what type of force?
s2008m [1.1K]
Gravitational I think would be the answer, Hope this helps!
8 0
3 years ago
Read 2 more answers
One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
Masteriza [31]

Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

c) 0 J/K

d)S= 61.53 J/K

Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

Q= 7190 J

a)

The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

b)

The entropy change of reservoir 101 K

S_2=\dfrac{7190}{101}\ J/K

S_2=71.18\ J/K

c)

The entropy change of the rod will be zero.

d)

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

3 0
3 years ago
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