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Citrus2011 [14]
4 years ago
7

Determine the values of m and n when the following average distance from the Sun to the Earth is written in scientific notation:

150,000,000,000 m.
Physics
1 answer:
Leviafan [203]4 years ago
3 0

Answer:

150000000000\ m=1.5\times 10^{11}\ m

Explanation:

A number can be written in the form of :

N=m\times 10^n

Where

m is the real number

n is any integer

In this case, the average distance from the Sun to the Earth is given,

d = 150000000000 meters

There are 10 zeroes in this number. We need to write this number in scientific notation. It is given by :

d=1.5\times 10^{11}\ m

So, the average distance from the Sun to the Earth is d=1.5\times 10^{11}\ m. Hence, this is the required solution.

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What is the same about the EM categories? What is different?
cricket20 [7]

Answer:

All 3 are CSS unit sizes which we can use for margins, fonts, borders etc.

Exp

CSS has four different unit sizes. These are:

Pixels (px)

Points (pt)

Ems (em)

Percentages(%)

These units are divided into two different groups. They are fixed and relative.

Pixels and points are fixed , whereas em and percentages are relative unit sizes. Relative unit sizes are good when creating scalable layouts.

Ems (em):

An em is a CSS unit that measures the size of a font. Originally, the em was equal to the width of the capital letter M, which is where its name originated.

It stands for "emphemeral unit" which is relative to the current font size.

The "em" is a scalable unit that  is used in web document media. Ems have mobile-device-friendly nature.

Pixels (px):

Pixels are fixed-size units that are used in screen media. One pixel is equal to one dot in computer. The problem with pixel unit is that it is not relative .

Points (pt):

Point values are only for print. A point is a unit of measurement use for real-life ink on paper. Generally, 72pts= 1 inch which is one real-life inch like on  a ruler. Point  is not recommended to use in web pages.

Generally, 1em=16px=12pt=100% if the body size is 100%.

Relative unit sized fonts change and fixed unit sized fonts remain the same.

For example,

body { font-size: 100%}

p{font-size: 16px}

8 0
3 years ago
The rate of rotation of the disk is gradually increased. The coefficient of static friction between the coin and the disk is 0.5
MrRissso [65]

Question is not complete and the missing part is;

A coin of mass 0.0050 kg is placed on a horizontal disk at a distance of 0.14 m from the center. The disk rotates at a constant rate in a counterclockwise direction. The coin does not slip, and the time it takes for the coin to make a complete revolution is 1.5 s.

Answer:

0.828 m/s

Explanation:

Resolving vertically, we have;

Fn and Fg act vertically. Thus,

Fn - Fg = 0 - - - - eq(1)

Resolving horizontally, we have;

Ff = ma - - - - eq(2)

Now, Fn and Fg are both mg and both will cancel out in eq 1.

Leaving us with eq 2.

So, Ff = ma

Now, Frictional force: Ff = μmg where μ is coefficient of friction.

Also, a = v²/r

Where v is linear speed or velocity

Thus,

μmg = mv²/r

m will cancel out,

Thus, μg = v²/r

Making v the subject;

rμg = v²

v = √rμg

Plugging in the relevant values,

v = √0.14 x 0.5 x 9.8

v = √0.686

v = 0.828 m/s

3 0
3 years ago
If a construction worker drops a wrench
Svetach [21]
To find velocity at a given moment, also known as instantaneous velocity, we need to know how to take the derivative of an equation;
you can take the derivative of s(t)=62t^2+ 375 by first moving the 2 in front of 162 and multiply both which well give you 324t and 375 will turn to 0
-16t^2 results in -32t
so our velocity at t=4 is -32(4) = -128ft per second
3 0
3 years ago
a stone is thrown straight upwards from the edge of a 24.0 m high cliff. It just misses the cliff on the way down, and it hits t
Simora [160]

Answer:

47.5 m/s

Explanation:

Given:

Δy = -24.0 m

v = -42.3 m/s

a = -9.8 m/s²

Find: v₀

v² = v₀² + 2aΔy

v² = (-42.3 m/s)² + 2 (-9.8 m/s²) (-24.0 m)

v = 47.5 m/s

5 0
3 years ago
A 55.0 kg runner who weighs 539.0 N is accelerating at 3.2 m/s2. After 2
drek231 [11]

Answer:

C. 352.0 kg-m/s

Explanation: Took the test on APEX

4 0
3 years ago
Read 2 more answers
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