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3 years ago

Evaluate 6kg 600g + 3kg 800g

Mathematics

2 answers:

Mkey [24]3 years ago

7 0

Answer:

10.4 kilograms

Step-by-step explanation:

zubka84 [21]3 years ago

5 0

Answer:

10.4kg or 10kg 400 g

Step-by-step explanation:

1kg-1000 grams

600grams-0.6 kg

800 grams=0.8kg

6.6 kg +3.8kg

=10.4kg

or convert it back to the question

so the answer will be 10kg 400g

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Read 2 more answers

Find the missing term.

igor_vitrenko [27]

Equations are used to relate equal expressions.

The missing term is: $\mathbf{ m -1}$

The equation is given as:

$\mathbf{\frac{m - n}{m^2 - n^2} + \frac{?}{(m -1)(m -n)} = \frac{2m}{m^2 - n^2}}$

Express $\mathbf{m^2 - n^2\ as\ (m - n)(m + n)}$

So, we have:

$\mathbf{\frac{m - n}{(m - n)(m + n)} + \frac{?}{(m -1)(m -n)} = \frac{2m}{(m - n)(m + n)}}$

Multiply through by $\mathbf{m - n}$

$\mathbf{\frac{m - n}{m + n} + \frac{?}{m -1} = \frac{2m}{m + n}}$

Collect like terms

$\mathbf{ \frac{?}{m -1} = \frac{2m}{m + n} - \frac{m - n}{m + n}}$

Take LCM

$\mathbf{ \frac{?}{m -1} = \frac{2m - m + n}{m + n} }$

$\mathbf{ \frac{?}{m -1} = \frac{m + n}{m + n} }$

Divide $\mathbf{ \frac{m + n}{m + n} }$

$\mathbf{ \frac{?}{m -1} = 1}$

Cross multiply

$\mathbf{ ? =(m -1)\times 1}$

$\mathbf{ ? =m -1}$

Hence, the missing term is: $\mathbf{ m -1}$

Evaluate 6kg 600g + 3kg 800g​

Evaluate 6kg 600g + 3kg 800g