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2 years ago

One number is 6 more than other number. Also, 7 times the smaller number is equal to 6 times the

Mathematics

1 answer:

julia-pushkina [17]2 years ago

4 0

Answer:

The numbers are 36 and 42

Step-by-step explanation:

Represent the two numbers by m and n, m being the larger number and n the smaller. Then

m = n + 6. also, 7n = 6m

Substitute n + 6 for m in the second equation: 7n = 6(n + 6).

Performing the indicated multiplication, we get 7n = 6n + 36, or n = 36.

Then m = n + 6, which here is m = 36 + 6 = 42.

The numbers are 36 and 42.

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For each of the finite geometric series given below, indicate the number of terms in the sum and find the sum. For the value of

kotykmax [81]

Answer:

Number of term N = 9

Value of Sum = 0.186

Step-by-step explanation:

From the given information:

Number of term N = $3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} + \cdots + 3 (0.5)^{13}$

Number of term N = $3 (0.5)^{5} + 3 (0.5)^{6} + 3 (0.5)^{7} +3 (0.5)^{8}+3 (0.5)^{9} +3 (0.5)^{10} +3 (0.5)^{11}+3 (0.5)^{12}+ 3 (0.5)^{13}$

Number of term N = 9

The Value of the sum can be determined by using the expression for geometric series:

$\sum \limits ^n_{k=m}ar^k =\dfrac{a(r^m-r^{n+1})}{1-r}$

here;

m = 5

n = 9

r = 0.5

Then:

$\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.5^5-0.5^{9+1})}{1-0.5}$

$\sum \limits ^n_{k=m}ar^k =\dfrac{3(0.03125-0.5^{10})}{0.5}$

$\sum \limits ^n_{k=m}ar^k =\dfrac{(0.09375-9.765625*10^{-4})}{0.5}$

$\sum \limits ^n_{k=m}ar^k =0.186$

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3 years ago

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Natali5045456 [20]

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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