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Inessa [10]
3 years ago
7

Please help me Find product

Mathematics
1 answer:
katrin [286]3 years ago
3 0

Simplify the expression.

2 x ^2 +2 x y − 4 y ^2

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Write an expression to represent:Nine less than the quotient of two and a number xxx.
Illusion [34]

Answer:

2/x - 9

Step-by-step explanation:

Hi there!

"9 less than" means we'll be subtracting 9 from our expression

"the quotient of 2 and a number x" means we'll be dividing 2 and x:

2/x - 9

I hope this helps!

3 0
3 years ago
What is the GCF of 40 and 21
trasher [3.6K]
40 and 21 do not have common factors, except for one. So the answer is 1.
5 0
3 years ago
Read 2 more answers
What is the solution?
andreyandreev [35.5K]

Answer:

Answer: w=2 and 2=6

Step-by-step explanation:

If you substitute 6 and 2 in for w they both work, making c the correct answer

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Need help please can someone help
Vladimir79 [104]
Assuming this problem is a simplification problem, the best way to simplify a problem like this would be to combine the fractions. to combine fractions with different denominators, even with variables, would be to multiply and get equal denominators, and then simplify. To get equal fractions we simply multiply the 2nd denominator on both sides in the 1st and vice versa. In this case for the top we have 1/(z-4) and 2/(z+8), so then we multiply the denominators and get (z+8)/(z-4)(z+8) and 2(z-4)/(z-4)(z+8). To get the final numerator then we first multiply out the 2 and get 2z-8 on the right, then combine the two fractions by adding them, and get 3z/(z-4)(z+8). For the denominator we repeat the same process. We multiply the denominators to get 4(z-6)/(z+8)(z-6) and 3(z+8)/(z-6)(z+8) we simplify the numerators by multiplying the 4 and 3 to get 4z-24 and 3z+24, and then subtract. We then get 4z-24-3z-24 and so z-48 and (z-48)/(z-6)(z+8). So now we have 3z/(z-4)(z+8) for a numerator and (z-48)/(z-6)(z+8) as a denominator. we can multiply z-8 on both sides of the final fraction to cancel out the z-8, and so get 3z/(z-4)/(z-48)/(z-6). As you can no longer simplify anything this is your final fraction.
8 0
4 years ago
URGENT HELP NEEDED WITH TRIANGLES/CIRCLES! IF ET = 31, DE = 65, AND DC= 74, FIND THE PERIMETER OF DCE.
snow_tiger [21]

ES = ET

and

DS = DR

and

CR = CT ( because each pair are tangents to the circle)


So ES = 31 and Ds = 65-31 = 34

and DR = 34 and CR = 74- 34 = 40.

CT = CR = 40

Therfore the line EC = 31 + 40 = 71


Finally the perimeter = 65 + 74 + 71 = 210 (answer)

6 0
3 years ago
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