Answer:
The astronaut's acceleration is 155.1 times the vehicle's acceleration
Explanation:
These effects due to Newton's third law of action and reaction. Since the forces are equal but in the opposite direction and each acting on a different body. We distance that the Force is F let's calculate the acceleration of the vehicle and the astronaut
Astronaut
F = 
a₁
Vehicle
F = 
a₁
F = 555.1 a₂
Let's match the equation
a₁ = 155.1 a₂
a₁ = 155.1 a₂
a₁ / a₂ = 155.1
The astronaut's acceleration is 155.1 times the vehicle's acceleration
We see that even when the acceleration of the vehicle is small, there is a very high multiplicative factor.
One method to improve this situation is that the vehicles fear some small retro-rocket vehicles to reduce their acceleration. This would have a very favorable impact on the astronaut's mission.
Another method would be for the astronaut himself to have the retro-rocket and control his acceleration.
Explanation:
It is given that,
Mass of an object is 13 kg
We need to find the mass of this object on the surface of Jupiter.
The mass of an object is the amount present in it. It it independent of location. It mass remains the same at Jupiter as well. Its does not depend on the gravity on that surface.
Hence, its mass will remain 13 kg on the surface of Jupiter.
The correct answer would be a molecule
Answer:
A. China rose
B. Methyl red
C. Phenolphthalein
Explanation:
An indicator is a substance used to detect the presence of an acid or base as characterized by the indicators color change. An indicator can either be natural or synthetic depending on whether it is obtained from naturally occurring substance (natural) or synthesized in a laboratory (synthetic).
A. China rose is a type of natural indicator that turns deep PINK or MAGENTA in the presence of an acid or GREEN in the presence of a base.
B. Methyl red is a synthetic Indicator that turns RED in the presence of an acid or YELLOW in the presence of a base.
C. Phenolphthalein is an organic dye that is originally colorless but turns PINK in the presence of a base but remains colorless in the presence of an acid or neutral substance.
