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AlexFokin [52]
3 years ago
12

After crossing the finish line, a race car slows down from 47 m/s to 32m/s in 3seconds. What is the car’s acceleration?

Physics
1 answer:
Lisa [10]3 years ago
7 0

Answer: -5 m/s^2

Explanation: a = v - u/t

                         = 32 - 47/3

                         = -15/3

                         = -5 m/s^2

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(a) The work done in moving the unit charge from point C to A is 7.62 x 10⁻³ J.

(b) The work done in moving the unit charge from point D to B is 7.62 x 10⁻³ J.

<h3>Work done in moving the charge from C to A</h3>

W = Fd

W = Kq²/d

  • from 0 origin to C, d = √(5² + 5²) = 7.07 m
  • from 0 origin to A, d = 5 m

W(C to A) = W(0 to C) + W(0 to A)

W(C \ to \ A) = - \frac{Kq^2}{7.07} + \frac{Kq^2}{5} \\\\ W(C \ to \ A)  = 0.0586 \ Kq^2\\\\W(C \ to \ A)  = 0.0586 \times 9 \times 10^9 \times (3.8\times 10^{-6})^2\\\\W(C \ to \ A)  = 7.62 \times 10^{-3} \ J

<h3>Work done in moving the charge from D to B</h3>
  • from 0 origin to D, d = √(5² + 5²) = 7.07 m
  • from 0 origin to B, d = 5 m

W(D to B) = W(0 to D) + W(0 to B)

W(D to B) = 7.62 x 10⁻³ J

Learn more about work done here: brainly.com/question/25573309

#SPJ1

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