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Over [174]
3 years ago
12

Helpppppppppppppppppp

Chemistry
1 answer:
VLD [36.1K]3 years ago
5 0
The correct answer would be C.)

100/2= 50
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What is/are the only reason(s) that a reaction may have a percent yield above 100%?
natta225 [31]
Usually, percent yield is lower than 100% because the actual yield is often less than the theoretical value. Reasons for this can include incomplete or competing reactions and loss of sample during recovery. Percent yield is always a positive value. I hope this can help you
6 0
3 years ago
Ni
Alchen [17]

Answer:

[Ar]3d^84s^2

Explanation:

From the question given, we are asked to write the condensed form of electronic configuration of nickel, Ni.

To do this, we simply write the symbol of the noble gas element before Ni in a squared bracket followed by the remaining electrons to make up the atomic number of Ni.

This is illustrated below:

The atomic number of Ni is 28.

The noble gas before Ni is Argon, Ar.

Therefore, the condensed electronic configuration of Ni is written as:

Ni(28) => [Ar]3d^84s^2

5 0
3 years ago
Elements in the same column of the periodic table of the elements all
Andre45 [30]

Answer:

Each column is called a group. The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.

Explanation:

6 0
3 years ago
Read 2 more answers
A is 3600 m away from B. Jack spent 720.0 s running from A to
laiz [17]

Answer:

Jacks average speed is 5 s per 1 m

3 0
3 years ago
Please help, I’ll mark your answer as brainliest
Sedaia [141]

Answer:

5.16 gm of SO3 formed with 2 g of S

Explanation:

Mole weight of  S in the equation = 2 * 32 = 62 gm

Mole weight os   O2  in the equation  6 * 16 =96 gm

From the BALANCED  equation   the grams of   S  to   O2  is

    62   to 96   so    2 g of  S will need  approx 3 gm of O2

            this shows that S is the limiting reactant------>

                            there will be O left over  (approx 1 gram)

SO3 mole weight produced from the equation is   2 (32)(3*16) = 160 gm

  62 gm of S produces 160 gm of SO3

   62/160 =  2 / x       x = 5.16 gm of  SO3   are formed

3 0
2 years ago
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