Answer:
Reduced, alkane
Explanation:
Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.
This reaction occurs at high temperature.
Alkane formed has a same number of carbon as aldehyde and ketone.
If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.
Here, acetaldehyde is reduced to form ethane.
So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.
Answer:
Student 3
Explanation:
This question lets us know something about how the density of a gas varies with temperature.
When a gas is heated, its molecules spread out and expand. When this happens, the volume of the gas increases. Remember that density is defined as mass/volume. Thus as the volume increases, the density of the gas decreases.
Therefore, the carbon dioxide rose up because the heat expanded the gas and it became less dense.
I think the answer to your question would be D.
Answer:
C6H6
Explanation:
C : 60.0 g*1 mol/12 .01g = 5.00 mol
H: 5.05 g * 1 mol/1.01 g= 5.10 mol
C:H = 5.00 mol : 5.10 mol = 1:1
CH is an empirical formula
Molar mass (12.01 +1.01)=13.02 g/mol
78.12g/mol /13.02 g/mol =6
Molecular formula is the empirical that was taken 6 times (CH)6 = C6H6
The
balanced chemical reaction will be:
C2H2 + 3/2O2 = 2CO2 +H2O
We are given the amount of C2H2 to be burned. This will be
our starting point.
<span>35.0 mol C2H2 ( 2 mol CO2/1 mol C2H2) = 70.0 mol O2</span>
<span>Therefore, the CO2 produced is 70.0 moles.</span>
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