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balu736 [363]
2 years ago
6

Please help, I’ll mark your answer as brainliest

Chemistry
1 answer:
Sedaia [141]2 years ago
3 0

Answer:

5.16 gm of SO3 formed with 2 g of S

Explanation:

Mole weight of  S in the equation = 2 * 32 = 62 gm

Mole weight os   O2  in the equation  6 * 16 =96 gm

From the BALANCED  equation   the grams of   S  to   O2  is

    62   to 96   so    2 g of  S will need  approx 3 gm of O2

            this shows that S is the limiting reactant------>

                            there will be O left over  (approx 1 gram)

SO3 mole weight produced from the equation is   2 (32)(3*16) = 160 gm

  62 gm of S produces 160 gm of SO3

   62/160 =  2 / x       x = 5.16 gm of  SO3   are formed

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Answer:

Equation of reaction:

a) 2HCl + Ba(OH)2 ==> CaCl2 + 2H2O

b) Molarity of base = 0.042 M.

Explanation:

Using titration equation

CAVA/CBVB = NA/NB

Where NA is the number of mole of acid = 2

NB is the number of mole of base = 1

CA is the molarity of acid =0.15M

CB is the molarity of base = to be calculated

VA is the volume of acid = 25 ml

VB is the volume of base = 44.45mL

Substituting

0.15×25/CB×44.45 = 2/1

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5 0
3 years ago
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7 0
3 years ago
A 0.708 g sample of a metal, M, reacts completely with sulfuric acid according to the reaction M ( s ) + H 2 SO 4 ( aq ) ⟶ MSO 4
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Answer:

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Explanation:

Step 1: Data given

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Vapor pressure of water at 25 °C = 0.03167 bar = 0.03126 atm

Step 2: The balanced equation

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Step 3: Calculate pH2

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0.9947 atm = 0.03126 atm + pressure of H2

Pressure of H2 = 0.9947 - 0.03126

Pressure of H2 = 0.96344 atm

Step 4: Calculate moles of H2

p*V=n*R*T

⇒ with p = The pressure of H2 = 0.96344 atm

⇒ with V = the volume of H2 = 0.275 L

⇒ with n = the number of moles H2 = TO BE DETERMINED

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = the temperature = 25°C = 298 Kelvin

n = (p*V)/(R*T)

n = (0.96344 * 0.275)/(0.08206*298)

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Step 5: Calculate moles of M

For 1 mole of H2 produced, we need 1 mole M

For 0.0108 moles of H2 we need 0.01083 moles of M

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Molar mass M = Mass M / moles M

Molar mass M = 0.708 grams / 0.01083 moles

Molar mass M = 65.37 g/mol

The metal has a molar mass of 65.37 g/mol

5 0
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