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2 years ago

Please help, I’ll mark your answer as brainliest

Chemistry

1 answer:

Sedaia [141]2 years ago

3 0

Answer:

5.16 gm of SO3 formed with 2 g of S

Explanation:

Mole weight of S in the equation = 2 * 32 = 62 gm

Mole weight os O2 in the equation 6 * 16 =96 gm

From the BALANCED equation the grams of S to O2 is

62 to 96 so 2 g of S will need approx 3 gm of O2

this shows that S is the limiting reactant------>

there will be O left over (approx 1 gram)

SO3 mole weight produced from the equation is 2 (32)(3*16) = 160 gm

62 gm of S produces 160 gm of SO3

62/160 = 2 / x x = 5.16 gm of SO3 are formed

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In order to gain one pound of body weight, the average person must consume 3500 more calories

Fed [463]

Answer:

17500 calories of chocolate bars are needed to eat to gain 5 pounds.

Explanation:

We can use ratios to calculate the answer using the information given in the question.

1 pound : 3500 grams

5 pounds : x grams

As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.

Method A:

To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.

x = 3500 × 5

x = 17500

Method B:

To solve for the answer x, we can convert the ratios into fractions.

1 / 5 = 3500 / x

3500 / x = 1 / 5

To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.

x = 5 × 3500

x = 17500

4 0

3 years ago

Name the two possible products in the precipitation reaction of copper (II) chloride and sodium phosphate. Use the charges on th

satela [25.4K]

Answer:

General equation for a double-displacement reaction:

AB + CD --> AC + BD

• sodium chloride – NaCl copper sulfate – CuSO₄

NaCl + CuSO₄ --> Na₂SO₄ + CuCl₂

The products formed are sodium sulfate and copper (II) chloride.

Copper (II) chloride forms a blue colored solution.

• sodium hydroxide – NaOH copper sulfate – CuSO₄

NaOH + CuSO₄ --> Na₂SO₄ + Cu(OH)₂

The products formed are sodium sulfate and copper (II) hydroxide.

Copper (II) hydroxide forms a blue colored solution.

• sodium phosphate – Na₂HPO₂ copper sulfate – CuSO₄

Na₂HPO₄ + CuSO₄ --> Na₂SO₄ + CuHPO₄

The products formed are sodium sulfate and copper (II) hydrogen phosphate.

Copper (II) hydrogen phosphate forms a blue colored solution.

• sodium chloride – NaCl silver nitrate – AgNO₃

NaCl + AgNO₃--> AgCl + NaNO₃

The products formed are silver chloride and sodium nitrate.

Silver chloride forms a white precipitate.

• sodium hydroxide – NaOH silver nitrate – AgNO₃

NaOH + AgNO₃ --> NaNO₃ + AgOH

The products formed are silver hydroxide and sodium nitrate.

Silver hydroxide forms a white precipitate.

• sodium phosphate – Na₂HPO₄ silver nitrate – AgNO₃

Na₂HPO₄ + AgNO₃ --> NaNO₃ + Ag₂HPO₄

The products formed are sodium nitrate and silver hydrogen phosphate.

Silver hydrogen phosphate forms a colorless solution.

Explanation:

5 0

3 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

3 years ago

What are minerals? What kinds of minerals are considered gems? (Site 1)

eimsori [14]

For your second question its Diamonds,Rubys, Emeralds.
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Minerals are solid: They don't droop or melt or evaporate.

Minerals are inorganic: They aren't carbon compounds like those found in living things.

Minerals are crystalline: They have a distinct recipe and arrangement of atoms.

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3 years ago

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velikii [3]

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3 years ago

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