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Anton [14]
2 years ago
6

What do you call the material or "stuff" that a wave travels through

Physics
2 answers:
frutty [35]2 years ago
8 0
C I think if not it’s B
statuscvo [17]2 years ago
3 0

Answer:

<em>a</em><em>.</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em>.</em>

Explanation:

<em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>a</em><em>t</em><em>t</em><em>e</em><em>r</em><em> </em><em>t</em><em>h</em><em>r</em><em>o</em><em>u</em><em>g</em><em>h</em><em> </em><em>w</em><em>h</em><em>i</em><em>c</em><em>h</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>w</em><em>a</em><em>v</em><em>e</em><em>s</em><em> </em><em>t</em><em>r</em><em>a</em><em>v</em><em>e</em><em>l</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>a</em><em>l</em><em>l</em><em>e</em><em>d</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em> </em><em>(</em><em> </em><em>p</em><em>l</em><em>u</em><em>r</em><em>a</em><em>l</em><em>,</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>a</em><em> </em><em>)</em><em>.</em><em> </em><em>b</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em> </em><em>o</em><em>f</em><em> </em><em>a</em><em> </em><em>m</em><em>e</em><em>c</em><em>h</em><em>a</em><em>n</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>w</em><em>a</em><em>v</em><em>e</em><em> </em><em>c</em><em>a</em><em>n</em><em> </em><em>b</em><em>e</em><em> </em><em>a</em><em>n</em><em>y</em><em> </em><em>s</em><em>t</em><em>a</em><em>t</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>m</em><em>a</em><em>t</em><em>t</em><em>e</em><em>r</em><em>,</em><em> </em><em>e</em><em>v</em><em>e</em><em>n</em><em> </em><em>a</em><em> </em><em>s</em><em>o</em><em>l</em><em>i</em><em>d</em><em>.</em>

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Sound waves travel fastest through a A) gas. B) liquid. C) solid. D) vacuum.
earnstyle [38]

Sound waves travel faster through <em>solids</em> than they do through gases or liquids.  <em>(C)  </em>They don't travel through vacuum at all.

Example:

Speed of sound in normal air . . . around 340 m/s

Speed of sound in water . . . around 1,480 m/s

Speed of sound in iron . . . around 5,120 m/s

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3 years ago
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By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
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A cannonball is fired at a 45.0° angle and an initial velocity of 670 m/s. Assume no air resistance. What is the vertical compon
elixir [45]

Answer:

<h3>473.8 m/s; 473.8 m/s</h3>

Explanation:

Given the initial velocity U = 670m/s

Horizontal velocity Ux = Ucos theta

Vertical component of the cannon velocity Uy = Usin theta

Given

U = 670m/s

theta = 45°

horizontal component of the cannonball’s velocity = 670 cos 45

horizontal component of the cannonball’s velocity = 670(0.7071)

horizontal component of the cannonball’s velocity = 473.757m/s

Vertical component of the cannonball’s velocity = 670 sin 45

Vertical component of the cannonball’s velocity  = 670 (0.7071)

Vertical component of the cannonball’s velocity  = 473.757m/s

Hence pair of answer is 473.8 m/s; 473.8 m/s

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3 years ago
Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude
labwork [276]

Answer:\tau=1.03\times 10^{-4}\ N-m

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

\tau=NIAB\ \sin\theta

Let us assume that, A=0.0008\ m^2

\theta is the angle between normal and the magnetic field, \theta=90^{\circ}-30^{\circ}=60^{\circ}

Torque is given by :

\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m

So, the net torque about the vertical axis is 1.03\times 10^{-4}\ N-m. Hence, this is the required solution.

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