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Anton [14]
3 years ago
6

What do you call the material or "stuff" that a wave travels through

Physics
2 answers:
frutty [35]3 years ago
8 0
C I think if not it’s B
statuscvo [17]3 years ago
3 0

Answer:

<em>a</em><em>.</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em>.</em>

Explanation:

<em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>a</em><em>t</em><em>t</em><em>e</em><em>r</em><em> </em><em>t</em><em>h</em><em>r</em><em>o</em><em>u</em><em>g</em><em>h</em><em> </em><em>w</em><em>h</em><em>i</em><em>c</em><em>h</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>w</em><em>a</em><em>v</em><em>e</em><em>s</em><em> </em><em>t</em><em>r</em><em>a</em><em>v</em><em>e</em><em>l</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>c</em><em>a</em><em>l</em><em>l</em><em>e</em><em>d</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em> </em><em>(</em><em> </em><em>p</em><em>l</em><em>u</em><em>r</em><em>a</em><em>l</em><em>,</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>a</em><em> </em><em>)</em><em>.</em><em> </em><em>b</em><em>u</em><em>t</em><em> </em><em>t</em><em>h</em><em>e</em><em> </em><em>m</em><em>e</em><em>d</em><em>i</em><em>u</em><em>m</em><em> </em><em>o</em><em>f</em><em> </em><em>a</em><em> </em><em>m</em><em>e</em><em>c</em><em>h</em><em>a</em><em>n</em><em>i</em><em>c</em><em>a</em><em>l</em><em> </em><em>w</em><em>a</em><em>v</em><em>e</em><em> </em><em>c</em><em>a</em><em>n</em><em> </em><em>b</em><em>e</em><em> </em><em>a</em><em>n</em><em>y</em><em> </em><em>s</em><em>t</em><em>a</em><em>t</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>m</em><em>a</em><em>t</em><em>t</em><em>e</em><em>r</em><em>,</em><em> </em><em>e</em><em>v</em><em>e</em><em>n</em><em> </em><em>a</em><em> </em><em>s</em><em>o</em><em>l</em><em>i</em><em>d</em><em>.</em>

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A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t
JulijaS [17]

Answer:

Dy = 111.66 [m]

t  = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

v_{f} = v_{o} - (g*t)\\

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

Dy=v_{o} *t+\frac{1}{2}*g*t

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

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The three vectors in Fig. 3-33 have magnitudes a = 3.00 m, b = 4.00 m, and c = 10.0 m and angle θ = 30.0°. What are
aliya0001 [1]

Answer:

a) a_{x} =3              b) a_{y} =0

c) b_{x} =3.46        d) b_{y} =2

e) c_{x} =0              f) c_{y} =10

g) p = -5.77                            h) q=5

Explanation:

Diagram for given question is attached below in fig 1

<h3>Part (a) (b)</h3>

for vector \vec{a}

θ = 0°

          a_{x} = 3 cos (0)\\a_{x} = 3\\a_{y} = 3 sin (0)\\a_{y} = 0

<h3>Part (c) (d)</h3>

for vector \vec{b}

θ = 30°

      b_{x} = 4 cos (30)\\b_{x} = 3.46\\b_{y} = 4 sin (30)\\b_{y} = 2

<h3>Part (e) (f)</h3>

for vector \vec{c}

θ = 90°

    c_{x} = 10 cos (90)\\c_{x} = 0\\c_{y} = 10 sin (90)\\c_{y} = 10

<h3>Part (g) (h)</h3>

                       \vec{c} = p\vec{a} + q\vec{b}

c =c_{x} \hat{i} + c_{y}\hat{j}\\as a_{y} =0\\c_{x} \hat{i} + c_{y}\hat{j} = pa_{x} \hat{i} +q(b_{x} \hat{i}  +b_{y} \hat{j} )\\c_{x} \hat{i}  = pa_{x} \hat{i} +qb_{x} \hat{i}\\c_{y}\hat{j}  =qb_{y}\hat{j}

                  q=\frac{c_{y}}{b_{y}} \\q=\frac{10}{2}\\q=5

c_{x} \hat{i}  = pa_{x} \hat{i} +qb_{x} \hat{i}\\0 = p(3) + (5)(3.46)\\p = -5.77

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3 years ago
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