1 year ago

Size relationships between parts of a whole are known as.

Physics

1 answer:

Stella [2.4K]1 year ago

8 0

Answer:

proportion

Explanation:

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The proper mean lifetime of a muon is 2.2 × 10–6 s. A beam of muons is moving with speed 0.6c relative to an inertial observer.

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3 years ago

You grab a car door handle in the summer (energy transfer to heat up the handle ____) and it burns you through energy transfer.

Cerrena [4.2K]

Answer: conduction

Explanation:

Because you are physically touching the handle

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3 years ago

A small 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 10^3 N/C. If th

tensa zangetsu [6.8K]

Answer:

The net charge is $67.89 \mu C$

Solution:

As per the question:

Mass of the plastic bag, m = 12.0 g = $12.0\times 10^{-3}\ kg$

Magnitude of electric field, E = $10^{3}\ N/C$

Angle made by the string, $\theta = 30^{\circ}$

Now,

To calculate the net charge, Q on the ball:

Vertical component of the tension in the string, $T = Tcos\theta$

Horizontal component of the tension in the string, $T = Tsin\theta$

Now,

Balancing the forces in the x-direction:

$Tsin\theta = QE$

$Q = {Tsin\theta}{E}$ (1)

Balancing the forces in the y-direction:

$Tcos\theta = mg$

where

g = acceleration due to gravity = $9.8\ m/s^{2}$

Thus

$T = \frac{mg}{cos\theta }$

$T = \frac{12.0\times 10^{-3}\times 9.8}{cos30^{\circ}} = 0.1357\ N$

Use T = 0.1357 N in eqn (1):

$Q = {0.1357\times sin30^{\circ}}{10^{3}} = 6.789\times 10^{- 5}\ C$

$Q = 67.89\times 10^{- 5}\ C = 67.89\mu C$

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3 years ago

What is the mass number of an atom with 5 protons and 7 neutrons?

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Boron I think look at the periodic table

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2 years ago

Read 2 more answers

An airplane flies at airspeed (relative to the air) of 280 km/h . The pilot wishes to fly due North (relative to the ground) but

MrRa [10]

Answer:

the pilot should head the plane $7.547^{\circ}$ towarrds south- west

Solution:

The airspeed of the airplane, v = 280 km/h

The velocity of the wind, v' = 52 km/h South-west

Angle, $\theta = 225^{\circ}$

Now, measured angle in the clockwise direction from North:

$sin225 = sin(\pi + 45) = - sin 45^{\circ}$

Now,

$vsinx - v'sin45 = 0$

$280sinx = 52sin45$

$x = sin^{- 1}(\frac{52}{280}\times \frac{1}{\sqrt{2}})$

$x = 7.547^{\circ}$ south- west

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2 years ago