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3 years ago

13

Compare and contrast power and work.

1 answer:

cestrela7 [59]3 years ago

6 0

Answer:

<u>Comparison</u>

Displacement and force are factors of both work and power

Work=<u>Force× Displacement</u>

power=(Force×Displacement)/time

Therefore power is the derivative of work with respect to time.

<u>Contrast</u>

Work is defined as a product of force and distance while power is the rate at which the work is done.

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What type of fault creates huge mountains

vladimir1956 [14]

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3 years ago

A force of 185 n is needed to keep a small boat moving at 2.39 m/s. what is the power required to keep the boat moving at the st

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2 years ago

a cyclist coasting down a 5.0 ◦ incline at a constant speed of 6.0 km/h because of air resistance. If the total mass of the bicy

Dvinal [7]

Answer:

$F_{net}= 85.41\ N$

Explanation:

mass of the bicycle + cyclist = 50 kg

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a cyclist coasting down a 5.0° incline

the downward velocity is constant, so net acceleration must be zero

the air drag must be equal to gravitational force downward along the ramp

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now for upward motion

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3 years ago

The dimension line is connected to the part being measured by _______________. A. Hidden lines B. Extension lines C. Visible lin

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3 years ago

Read 2 more answers

f an arrow is shot upward on the moon with velocity of 35 m/s, its height (in meters) after t seconds is given by h(t)=35t−0.83t

inysia [295]

Answer:

The velocity of the arrow after 3 seconds is 30.02 m/s.

Explanation:

It is given that,

An arrow is shot upward on the moon with velocity of 35 m/s, its height after t seconds is given by the equation:

$h(t)=35t-0.83t^2$

We know that the rate of change of displacement is equal to the velocity of an object.

$v(t)=\dfrac{dh(t)}{dt}\\\\v(t)=\dfrac{d(35t-0.83t^2)}{dt}\\\\v(t)=35-1.66t$

Velocity of the arrow after 3 seconds will be :

$v(t)=35-1.66t\\\\v(t)=35-1.66(3)\\\\v(t)=30.02\ m/s$

So, the velocity of the arrow after 3 seconds is 30.02 m/s. Hence, this is the required solution.

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3 years ago