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aev [14]
3 years ago
12

You want to have 80000 college fund in 12 years. How much will you have to deposit now under the scenario below. Assume that you

make no deposits into the account after the initial deposit.
An APR of 7.5​% compounded daily
Mathematics
1 answer:
stealth61 [152]3 years ago
3 0

9514 1404 393

Answer:

  $32,528.58

Step-by-step explanation:

For simplicity, we'll assume each year has 365 days.

The future value A of principal amount P at rate r compounded daily for t years is ...

  A = P(1 +r/365)^(365t))

We want P when A = 80,000, r = 0.075, and t = 12.

  P = A/(1 +r/365)^(365t)

  P = $80000/(1+0.075/365)^(365·12) ≈ $32,528.58

You will have to deposit about $32,528.58.

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erik [133]
In mathematics it’s another term for isometry
6 0
3 years ago
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How could you convert a rate of 18,000 mph to miles per second
Dmitrij [34]
Hi there,

(18000 miles / 1 hour)(1 hour / 60 minutes)(1 minute / 60 seconds) adds up to <span>18000 miles / 3600 seconds, which then adds up to </span><span>5 miles / 1 second...
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you should get a total of 5 miles per second

I hope I helped :)
6 0
3 years ago
6 Jenna bought n notebooks which cost 5 dollars each, and 3 pens which cost r dollars each. How much money did she spend?
lana66690 [7]
The answer should be 5n+3r
8 0
3 years ago
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one
d1i1m1o1n [39]

Answer:

0.9855 or 98.55%.

Step-by-step explanation:

The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:

P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855

The probability  that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.

8 0
3 years ago
Complete the factorization of 3x ^ 2 - 10x + 8 3x^ 2 -10x+8=(x- Box x-4)
aniked [119]

Answer:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

Step-by-step explanation:

The general form of a quadratic polynomial is given by:

ax^2+bx+c    (1)

You have the following polynomial:

3x^2-10x+8    (2)

In order to complete the factorization you can use the quadratic formula, to obtain the roost of the polynomial. The quadratic formula is given by:

x_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}    (3)

By comparing the equation (1) with the equation (2) you obtain:

a = 3

b = -10

c = 8

Then, you replace these values in the equation (3):

x_{1,2}=\frac{-(-10)\pm \sqrt{(-10)^2-4(3)(8)}}{2(3)}\\\\x_{1,2}=\frac{10\pm2}{6}\\\\x_1=2\\\\x_2=\frac{4}{3}

Then, the factorization of the polynomial is:

3x^2-10x+8=(x-x_1)(x-x_2)=(x-2)(x-\frac{4}{3})

5 0
3 years ago
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