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Rashid [163]
3 years ago
6

A fair charges an admission fee of 3 dollars for each person. Let c be the cost of admission in dollars for p people wrote an eq

uation relating c to p graph your answer
Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

c = 3p

graph is in the image attached

Step-by-step explanation:

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It should be 140 degrees.
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What is 7.2 times 10 to the 7th power times 14.6 x 10 to the 5th power?
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7 x 10^{7}  times 14.6 x10^{5}

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Final Answer 102.2 and 10^{5}

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the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
3 years ago
X-intercept =2; y-intercept =4/3 Find he equation of the line​
Neko [114]
Y = mx + b
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y = 4/3 + 2
7 0
3 years ago
Help with this problem^
Fittoniya [83]
This formula is the exposition of 8 and equals to 6 how u ask ? well if u 8 minus 2 u get 6 than add 6
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3 years ago
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