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saul85 [17]
3 years ago
9

What voltage (potential difference)must be applied to a 26 1

Physics
1 answer:
12345 [234]3 years ago
3 0

Answer:

26v

....................

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A ductile metal wire has resistance R. What will be the resistance of this wire in terms of R if it is stretched to three times
Ira Lisetskai [31]

Answer:

9R

Explanation:

We know that the resistance is R=\rho *\frac{L}{A}.

If we stretch the wire to a new length L2 = 3L, the cross-sectional area will also change. If the cross-sectional area doesn't change throughout the wire, we can say that:

Volume = L*A = 3L * A2    being A2 the new area after stretching the wire.

Since the volume remains the same we conclude that A2 = A/3

With this information, we calculate the new resistance:

R2=\rho *\frac{L2}{A2}=\rho *\frac{3*L}{A/3}=\rho * 9 * \frac{L}{A}

Since R=\rho *\frac{L}{A}, and by simple inspection of the previous equation, we get:

<em>R2 = 9*R</em>

6 0
3 years ago
A database that is flexible and easy to use was recently installed. the data is stored in rows and columns much like a spreadshe
andre [41]

The correct answer is Relational Database

7 0
3 years ago
. Calculate the kinetic energy of a 100.0-kg meteor approaching the Earth at a speed of 10.0 km/s. Remember that 1 km = 1000 m.
anastassius [24]
Ke = (1/2)mv²

m = 100kg, v = 10 km/s = 10*1000 = 10000m/s

Ke = (1/2)*100*10000 

Ke = 500000 Joules
7 0
3 years ago
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Suppose an individual is lying on his stomach with sheets of paper stacked on his back. If each sheet of paper has a mass of 0.0
AURORKA [14]

Answer:

N = 177843 sheets

Explanation:

We are given;

Mass;m = 0.0035 kg

Pressure; p = 101325 pa = 101325 N/m²

L = 0.279m

W = 0.216m

The weight of N sheets is N(mg)

Where;

m is the mass of one sheet

N is number of sheets

g is the acceleration due to gravity.

The pressure equals weight divided by the area on which the weight presses:

Thus,

p= F/A = Nmg/(L•W)

Therefore, making N the subject;

N = pLW/(mg)

N = 101325 x 0.279 x 0.216/ (0.0035 x 9.81)

N = 177843

5 0
3 years ago
How many joules of heat would be required to heat 0.5 kg of aluminum by 2 kelvin
melisa1 [442]
0.902 joules of energy
4 0
3 years ago
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