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QveST [7]
3 years ago
12

In the reaction _S+302 +2SO3, what coefficient should be placed in front of the S to balance the reaction?

Physics
1 answer:
lys-0071 [83]3 years ago
5 0

Answer:

B. 2

Explanation:

The reaction expression is given as:

                _S  + 3O₂   →  2SO₃

Now let us balanced the expression;

  On the product side we have 2 moles of S

   On the reactant side we should have 2moles of S

So, we put the coefficient 2 to balance the expression;

   We have 6 moles oxygen on both sides

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Explanation:

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What happens when an electron moves from an excited state to the ground state?
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<span>When an electron moves from an excited state to the ground state, "Energy releases"

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3 years ago
is this true or false? an object with a mass of 9.0kg has an acceleration of 3m/s2. the force acting on it is 3N
ludmilkaskok [199]

The answer is "False". The force acting on the object is 27 N.

According to Newton's second law, when a force <em>F</em> acts on am object of mass <em>m</em>, it produces an acceleration <em>a</em>. The force is given by the expression,

F=ma

Thus, if the body has a mass of 9.0 kg and if it has an acceleration of 3 m/s², then, on substituting the values in the equation for force,

F=ma\\ =(9.0kg)(3m/s^2)\\ =27N

Thus, it can be seen that the force acting on the body is 27 N and not 3 N as is mentioned in the statement. Hence the statement is false.

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3 years ago
As the mass of an object increases, it’s inertia will
Scrat [10]

Answer:

Inertia is the property of mass that resists change. Therefore, it is safe to say that as the mass of an object increases so does its inertia.

Explanation:

7 0
2 years ago
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help me pass the test please there is a couple of questions in my profile to answer i am leaving this one for you to help ​
kompoz [17]

Answer:

0.5 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

Acceleration (a) =?

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 10 m/s

Time (t) = 20 s

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a = (v – u) / t

a = (10 – 0) / 20

a = 10/20

a = 0.5 m/s²

Therefore, the acceleration of the car is 0.5 m/s².

6 0
2 years ago
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