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Galina-37 [17]
2 years ago
10

2. What kinetic energy has a 1 tonne car travelling at 15 m/s?

Physics
1 answer:
solong [7]2 years ago
3 0

Answer:

225000j

Explanation:

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PHYSICAL SCIENCE: What are some methods used to control the types and sources of pollution?
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Gaseous emissions are industrial products such as sulfur dioxide, carbon monoxide, and oxides of nitrogen also released during various manufacturing operations. Particulate control. Methods for particulate control tend to operate on a common principle.

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2 years ago
How many meters did the car go in the first 4 seconds?​
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Are there numbers on the y axis?
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3 years ago
Which of the following statements about the conservation of momentum is not correct? Momentum is conserved for a system of objec
Olin [163]

Answer:

wrong statement :  Momentum is not conserved for a system of objects in a head-on collision.

Explanation:

In a head on collision of two objects , two equal and opposite forces are created at the point of collision . These two forces create two impulses in opposite direction which results in equal and opposite changes in momentum in each of them . Hence net change in momentum is zero. In this way momentum is conserved in head on collision of two objects.

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3 years ago
In an electronic transition an atom can not emit what?
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█ Question <span>█

</span><span>In an electronic transition, an atom cannot emit what?

</span>█ Answer █

When an electronic transition is occurring, an atom cannot emit ultra-violet light. 

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7 0
3 years ago
A ball is thrown up at a speed of 20 m/s.
ioda

Given:

(Initial velocity)u=20 m/s

At the maximum height the final velocity of the ball is 0.

Also since it is a free falling object the acceleration acting on the ball is due to gravity g.

Thus a=- 9.8 m/s^2

Now consider the equation

v^2-u^2= 2as

Where v is the final velocity which is measured in m/s

Where u is the initial velocity which is measured in m/s

a is the acceleration due to gravity measured in m/s^2

s is the displacement of the ball in this case it is the maximum height attained by the ball which is measured in m.

Substituting the given values in the above formula we get

0-(20x20)= 2 x- 9.8 x s

s= 400/19.6= 20.41m

Thus the maximum height attained is 20.41 m by the ball

6 0
2 years ago
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