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tensa zangetsu [6.8K]

3 years ago

8

Expresa, en unidades del Sistema Internacional, la siguiente cantidad:

1 answer:

Alenkinab [10]3 years ago

6 0

Answer:

hola

Explanation:

me no se , lo siento :/

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What direct current in A will produce the same amount of thermal energy, in a particular resistor, as an alternating current tha

vodomira [7]

Answer:

$I_{rms}= 4.314 AExplanation:According to the definition of the root mean square value of current, the value of direct current which passes through the same circuit in which an alternating current is passing and producing same amount of heat as the direct current produced is called root mean square value of current. So, the relation between the root mean square value of current and the peak value of alternating current is given by [tex]I_{rms}=\frac{I_{0}}{\sqrt{2}}$

$I_{rms}=\frac{6.1}}{\sqrt{2}}$

[tex]I_{rms}= 4.314 A

6 0

3 years ago

Hi please zoom in to see it clearly, uh you don’t have to answer them all but it would be nice !!! (no links please) :D

kap26 [50]

12.could be D
13.A
14.D
15.C
16.A

3 0

3 years ago

A sled starts from rest,

Marrrta [24]

Answer:

25.6 m/s

Explanation:

Draw a free body diagram of the sled. There are two forces acting on the sled:

Normal force pushing perpendicular to the hill

Weight force pulling straight down

Take sum of the forces parallel to the hill:

∑F = ma

mg sin θ = ma

a = g sin θ

a = (9.8 m/s²) (sin 38.0°)

a = 6.03 m/s²

Given:

v₀ = 0 m/s

a = 6.03 m/s²

t = 4.24 s

Find: v

v = at + v₀

v = (6.03 m/s²) (4.24 s) + (0 m/s)

v = 25.6 m/s

5 0

3 years ago

A light ray in glass (n=1.5) hits the air-glass interface at an angle of 10 degrees from the normal. What angle from the normal

jekas [21]

Answer:

The angle from the normal is 15.1°.

Explanation:

We can find the angle by using Snell's law:

$n_{1}sin(\theta_{1}) = n_{2}sin(\theta_{2})$

Where:

n₁: is the first medium (glass) = 1.5

n₂: is the second medium (air) = 1.0

θ₁: is the first angle (in the glass) = 10°

θ₂: is the second angle (in the air) =?

$\theta_{2} = arcsin(\frac{n_{1}sin(\theta_{1})}{n_{2}}) = arcsin(\frac{1.5*sin(10)}{1.0}) = 15.1 ^{\circ}$

Therefore, the angle from the normal is 15.1°.

I hope it helps you!

7 0

3 years ago

The rectangular plates in a parallel-plate capacitor are 0.063 m × 5.4 m. A distance of 3.5 × 10–5 m separates the plates. The p

djverab [1.8K]

Answer:

capacitance of the capacitor = 0.18 μ F

Explanation:

Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²

distance between the plate d = 3.5 × 10–5 m

dielectric value for Teflon K = 2.1

capacitance of capacitor = ?

Formula for capacitance of parallel plate is as follows ,

$C= \frac{K\epsilon_0 A}{d}$ (Where $\epsilon_0 = 8.82 \times 10^-12\ \frac{F}{m}$ )

putting the values in the equation,

C = $\frac{2.1\times8.82\times10^-12\times0.3402 }{3.5\times10^-5}$ $=0.18\times 10^-6$ =0.18 μ F

4 0

3 years ago