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Anit [1.1K]
3 years ago
15

Twenty-seven pounds (27 lb) of chlorine gas is used for treating 750,000 gal of water each day. The chlorine used up by the micr

oorganisms in the water is measured to be 2.6 mg/L. What is the residual (excess) chlorine concentration in the treated water
Chemistry
1 answer:
worty [1.4K]3 years ago
5 0

Answer:

1.7137\ \text{mg/L}

Explanation:

Chlorine gas available = 27 lbs = 27\times 453.59237=12247\ \text{g}

Amount of water used each day = 750000 gal = 750000\times3.785411784=2839058.84\ \text{L}

Rate at which chlorine gas used = 2.6 mg/L

Chlorine gas used

2839058.84\times 2.6\times 10^{-3}=7381.55\ \text{g}

Residual content of chlorine = 12247-7381.55=4865.45\ \text{g}

Concentration of the residual chlorine is given by

\dfrac{4865.45}{2839058.84}=0.0017137\ \text{g/L}=1.7137\ \text{mg/L}

Concentration of the residual chlorine is 1.7137\ \text{mg/L}.

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Answer:

\large \boxed{\text{21.6 L}}

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:        180.16

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m/g:      24.5

(a) Moles of C₆H₁₂O₆

\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}

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We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37  °C

(i) Convert the temperature to kelvins

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(ii) Calculate the volume

\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}

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Answer:

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Based on combined gas law, gases under the same pressure, temperature and volume have the same number of moles. With this information we can say the rigth statement is:

<h3>C. The balloon with CH4 has the same moles of gas molecules as the balloon with H2</h3>
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The answer is A :) your welcome hope this helps
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35 b.
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