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romanna [79]
3 years ago
8

How many moles are in 2.3x1024 g of Ag? Plz help!!

Chemistry
1 answer:
ziro4ka [17]3 years ago
7 0

Answer:

              2.13 × 10²² moles

Explanation:

Relation between Mole and Mass is,

                             Mole = Mass / M.Mass

Putting values,

                             Mole = 2.3 × 10²⁴ g / 107.87 g/mol

                             Mole = 2.13 × 10²² moles

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Consider the diagram. Which postulate of the kinetic-molecular theory best describes the event in the diagram?
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Answer : Option B) All collisions between particles are perfectly elastic.

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The collisions are perfectly elastic because when gases are left alone in a container they don't seem to lose energy and do not spontaneously get converted into a liquid, also energy is not lost during collisions.

In the diagram given above one can interpret that the gaseous molecules are in random motion inside the container and when they collide with other molecule of gas they do not lose energy. Therefore, this shows perfectly elastic collisions.

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3 years ago
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Use the Rydberg equation to calculate the wavelength (in Å) of the photon absorbed when a hydrogen atom undergoes a transition f
ivolga24 [154]

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1024Å

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Using equation (1), we have

1/λ = 1.097 x 10^{7}(\frac{1}{3^{2} }- \frac{1}{1^{2} })

    = 1.097 x 10^{7} (\frac{1}{9} -\frac{1}{1} )

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λ = -\frac{1}{9763300}

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To convert to Å, we have

λ = \frac{1.024 x 10^{-7} }{10^{-10} } = 1024Å  

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