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2 years ago

How many moles are in 2.3x1024 g of Ag? Plz help!!

Chemistry

1 answer:

ziro4ka [17]2 years ago

7 0

Answer:

2.13 × 10²² moles

Explanation:

Relation between Mole and Mass is,

Mole = Mass / M.Mass

Putting values,

Mole = 2.3 × 10²⁴ g / 107.87 g/mol

Mole = 2.13 × 10²² moles

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2 years ago

1. Magnesium chloride solution reacts with silver nitrate solution to form magnesium nitrate

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a. 1,4332 g

b. 7.54~g

<h3>Further explanation</h3>

Given

Reaction

MgCl2 (s) + 2 AgNO3 (aq) → Mg(NO3)2 (aq) + 2 AgCl (s)

20 cm of 2.5 mol/dm^3 of MgCl2

20 cm of 2.5 g/dm^3 of MgCl2

Required

the mass of silver chloride - AgCl

Solution

a. mol MgCl2 :

$\tt 20~cm^3=20\times 10^{-3}~dm^3\\\\mol=M\times V\\\\mol=2.5~mol/dm^3\times 20\times 10^{-3}DM^3=0.05$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.05=0.1

mass AgCl(MW=143,32 g/mol)= 0.1 x 143,32=1,4332 g

b. mol MgCl2 (MW=95.211 /mol):

$\tt mol=M\times V\\\\mol=\dfrac{2.5~g/dm^3}{95,211 g/mol}=0.0263~mol/dm^3$

From equation, mol AgCl = 2 x mol MgCl2=2 x 0.0263=0.0526

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2 years ago

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Delicious77 [7]

Answer:

Explanation:

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2 years ago