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4 years ago

Which of the following is an example of a homogeneous mixture?

2 answers:

ozzi4 years ago

7 0

D. Apple Juice because in fruit salad you can see the ingredients [apple, berries, lettuce,etc] and you can pick them out and sand at the beach is mixture of rocks and other types of minerals. Also, granite is a heterogeneous mixture because you can see the differences in color or texture.

Nastasia [14]4 years ago

4 0

A. sand at the beach

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Is the bond length in HCl the same as that in DCl? The wavenumbers of the J = 0  1 rotational transitions for H35Cl and 2H35Cl

konstantin123 [22]

I’m sorry i do not know

4 0

3 years ago

Fill in the missing data point. Show all calculations leading to an answer.

Aleksandr-060686 [28]

Answer:

1090 mmHg

Explanation:

We know that with gases we must use a Kelvin temperatures, so let’s try a plot of pressure against the Kelvin temperature.

We can create a table as follows

t/°C T/K p/mmHg

10 283 726

20 293 750

40 313 800

70 343 880

100 373 960

150 423 ???

I plotted the data and got the graph in the figure below.

It appears that pressure is a linear function of the Kelvin temperature.

y = mx + b

where x is the slope and b is the y-intercept.

===============

Calculate the slope

I will use the points (275, 700) and (380, 975).

Slope = Δy/Δx = (y₂ - y₁)/(x₂ -x₁) = (975 -700)/(380 – 275) = 275/105 = 2.619

So,

y = 2.619x + b

===============

Calculate the intercept

When x = 275, y = 700.

700 = 2.619 × 275 + b

700 = 720 + b Subtract 720 from each side and transpose.

b = -20

So, the equation of the graph is

y = 2.619x -20

===============

Calculate the pressure at 423 K (150°C)

y = 2.619 × 423 - 20

y = 1110 - 20

y = 1090

At 150 °C, the pressure 1090 mmHg.

The point is approximately at the position of the black dot in the graph.

7 0

3 years ago

5vocabuoart word in with meaning the module

NemiM [27]

Answer:

yo gotta be more specific

5 0

3 years ago

The unsaturated hydrocarbon butadiene (C4H6) dimerizes to 4-vinylcyclohexene (C8H12). When data collected in studies of the kine

UkoKoshka [18]

Answer:

The dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

$R=k[C_4H_6]^2$

Explanation:

$2C_4H_6\rightarrow C_8H_{12}$

The rate of the reaction ;

$R=k[C_4H_6]^x$

As given in the question , that graph of time verses $\frac{1}{[C_4H_6]}$ was linear but plots of $[C_4H_6]$ or $\ln[C_4H_6]$ was curved.

Generally:

Graph of time verses $[concentration]$ for zero order reaction is linear with negative slope.

Graph of time verses $\ln [concentration]$ for secon order reaction is linear with negative slope.

Graph of time verses $\frac{1}{[concentration]}$ for secon order reaction is linear with positive slope.

So, the dimerization of butadiene to 4-vinylcyclohexene folows second order kinetics and its rate law will be given by :

$R=k[C_4H_6]^2$

3 0

3 years ago

If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pre

mario62 [17]

Answer:

627.4 mmHg

Explanation:

From Gay-Lussac law:

$\frac{p1}{t1} = \frac{p2}{t2}$

p1 = 760 mmHg

t1 = 343 K

t2=283.15 K

$p2 = p1 \times \frac{t2}{t1}$

$p2 = 760 \times \frac{283.15}{343.0}$

$p2 = 627.4 \: mmhg$

5 0

3 years ago