A ball is launched into the sky at 54.4 feet per second from a 268.8 meter tall building. The equation for the ball’s height, h,
at time t seconds is h = -3.2t^2 + 54.4t + 268.8. When will the ball strike the ground?
2 answers:
Answer:
4.42 seconds is the correct answer
Step-by-step explanation:
Answer:
7.41
Step-by-step explanation:
Vertical component:
S = 268.8
U = 0
V =?
A = 9.8
T=?
S = ut + 0.5at^2. u = 0
268.8 = 0.5x9. 8xt^2
T = 7.41 seconds
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56x56=3136 you would divide that by 500 and get 6.272
Answer:
Step-by-step explanation:
= 2k - x
Given that k = 9, x = 5
= 2(9) - 5
= 18 - 5
= 13
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Hope his helped!
<h3>~AH1807</h3>
The answer is 532 full your welcome yay fun
Answer:
7 4/5
Step-by-step explanation:
2 2/5 = 12/5
3 1/4 = 13/4
12/5 x 13/4 = 156/20 = 7 16/20
7 16/20 / 4 = 7 4/5
0 = x because 0 + 5 = 5 plus 2 = 7
