Question

A ball is launched into the sky at 54.4 feet per second from a 268.8 meter tall building. The equation for the ball’s height, h, at time t seconds is h = -3.2t^2 + 54.4t + 268.8. When will the ball strike the ground?

Answer 1

Answer:

4.42 seconds is the correct answer

Step-by-step explanation:

Answer 2

Answer:

7.41

Step-by-step explanation:

Vertical component:

S = 268.8

U = 0

V =?

A = 9.8

T=?

S = ut + 0.5at^2. u = 0

268.8 = 0.5x9. 8xt^2

T = 7.41 seconds