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riadik2000 [5.3K]
3 years ago
7

A ball is launched into the sky at 54.4 feet per second from a 268.8 meter tall building. The equation for the ball’s height, h,

at time t seconds is h = -3.2t^2 + 54.4t + 268.8. When will the ball strike the ground?
Mathematics
2 answers:
pychu [463]3 years ago
8 0

Answer:

4.42 seconds is the correct answer

Step-by-step explanation:

worty [1.4K]3 years ago
5 0

Answer:

7.41

Step-by-step explanation:

Vertical component:

S = 268.8

U = 0

V =?

A = 9.8

T=?

S = ut + 0.5at^2. u = 0

268.8 = 0.5x9. 8xt^2

T = 7.41 seconds

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8 0
3 years ago
Please help its due tommorrow morning!
LenaWriter [7]

Answer: $324

Step-by-step explanation:

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4 0
3 years ago
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dimaraw [331]

Answer:

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Step-by-step explanation:

3 0
3 years ago
4. Neelam's annual income is Rs. 288000. Her annual savings amount
Vikki [24]

Answer:

The ratio of her savings to expenditure <u>1 : 7</u>.

Step-by-step explanation:

Given:

Neelam's annual income is Rs. 288000.

Her annual savings amount  to Rs. 36000.

Now, to get the ratio of her savings to her expenditure:

So, we get the expenditure first:

Expenditure = Income - Savings.

Expenditure = 288000 - 36000 = Rs. 252000.

Now, <em>the ratio of savings to expenditure:</em>

\frac{Savings}{Expenditure} =\frac{36000}{252000}

\frac{Savings}{Expenditure} =\frac{1}{7}

Thus, Savings:Expenditure = 1:7.

Therefore, the ratio of her savings to expenditure 1 : 7.  

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