As we know that the standard equation of circle is 
, where <em>r</em> is the radius of circle and centre at <em>(h,k) </em>
Now , as the circle passes through <em>(2,9)</em> so it must satisfy the above equation after putting the values of <em>h</em> and <em>k</em> respectively
After raising ½ power to both sides , we will get <em>r = +5 , -5</em> , but as radius can never be -<em>ve</em> . So <em>r = +</em><em>5</em><em> </em>
Now , putting values in our standard equation ;
<em>This is the required equation of </em><em>Circle</em>
Refer to the attachment as well !
Answer:
30,000
Step-by-step explanation:
50% remaining = 10500
After deposit: 2×10500 = 21000
210000 : 70%
X : 100%
21000/70 = X/100
X = 30,000
Vertical reflection over the x-axis, shrink of 1/3, right 3, up 2
Answer:
1.344 cubic units
Step-by-step explanation:
Given data
Base edge a= 1.2
Hieght= 2.8
The expression for the volume of a pyramid is
V= a^2h/3
substitute
V= 1.2^2* 2.8/3
V= 1.44*2.8/3
V= 4.032/3
V= 1.34cubic units
Answer:
Step-by-step explanation:
Use the distibutivve property to multiply -6 by 1.4 - r
Then move over 6r to the front
