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goldfiish [28.3K]

3 years ago

10

A 0.25 kg harmonic oscillator has a total mechanical energy of 4.1 J. If the oscillation amplitude is 20.0 cm, what is the oscil

lation frequency?a. 4.6 Hz b. 1.4 Hz c. 2.3 Hz d. 3.2 Hz

1 answer:

Akimi4 [234]3 years ago

8 0

Answer:

4.3hz

Explanation:

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Technician A says a that a voltmeter can be used to monitor the output signal of an optical sensor. Technician B says that optic

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Answer:

B. Technician B only

Explanation:

An oscilloscope can be used to check the output signal of an optical sensor. The oscilloscope has the functioning of viewing the results in the form of waveform and its time scale settings can be altered to meet the requirements of the results.

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3 years ago

Two loudspeakers emit sound waves of the same frequency along the x-axis. The amplitude of each wave is a. The sound intensity i

leonid [27]

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are $\dfrac{\lambda}{2}$

Thus; for both speakers; the wavelength of the sound is:

$\dfrac{\lambda}{2} = (10+30) cm$

$\dfrac{\lambda}{2} = (40) cm$

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

$\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o$

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

$\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o$

$\pi \ rad = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o$

$\pi \ rad = \dfrac{2 \pi}{8}+ \Delta \phi_o$

$\pi \ rad = \dfrac{ \pi}{4}+ \Delta \phi_o$

$\Delta \phi_o = \pi -\dfrac{ \pi}{4}$

$\Delta \phi_o = \dfrac{ 4\pi - \pi}{4}$

$\Delta \phi_o = \dfrac{ 3\pi}{4} \ rad$

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

$\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o$

$\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad$

$\Delta \phi = \dfrac{3 \pi}{4} \ rad$

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

$A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)$

$A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)$

$A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)$

A = 0.765a

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2 years ago

Which is a chemical reaction? Select one: a. a peanut shell cracking open into two halves b. solid chocolate melting into liquid

raketka [301]

My best educated guess would be d

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3 years ago

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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre

Evgen [1.6K]

Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of $1.20 \ \Omega$

Answer:

The current is $I = 0.0007 41 \ A$

Explanation:

From the question we are told that

The area is $A = 8.00 \ cm^2 = 8.0 *10^{-4} \ m^2$

The initial magnetic field at $t_o = 0 \ seconds$ is $B_i = 0.500 \ T$

The magnetic field at $t_1 = 0.99 \ seconds$ is $B_f = 1.60 \ T$

The resistance is $R = 1.20 \ \Omega$

Generally the induced emf is mathematically represented as

$\epsilon = A * \frac{B_f - B_i }{ t_f - t_o }$

=> $\epsilon = 8.0 *10^{-4} * \frac{1.60 - 0.500 }{ 0.99- 0 }$

=> $\epsilon = 0.000889 \ V$

Generally the current induced is mathematically represented as

$I = \frac{\epsilon}{R }$

=> $I = \frac{0.000889}{ 1.20 }$

=> $I = 0.0007 41 \ A$

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2 years ago