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Aleksandr [31]
2 years ago
12

Which countries were considered the three major Axis Powers?

Physics
1 answer:
7nadin3 [17]2 years ago
8 0
B. JAPAN, GERMANY, and ITALY

The main Axis powers were Japan, with Emperor Hirohito as leader; Germany, with Adolf Hitler as leader; and Italy, with Benito Mussolini as leader. They were all dictators.

The Axis powers began to form in 1936

15th October 1936 - Germany and Italy signed a friendship treaty - Rome-German Axis.
25th November 1936 - Germany and Japan signed a treaty against communism - Anti-Comintern Pact

22nd May 1939 - Germany and Italy signed a stronger alliance - Pact of Steel
27th September 1940 - Japan signed the Pact of Steel - It became known as the Tripartite Pact.
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Which of the following is an impact of trampling of beach grass by humans and vehicles?
grigory [225]
Increase in sea water pollution
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DEFINE REFRACTION? describe how a ray of light is refracted when it passes through a glass block​
jek_recluse [69]
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8 0
2 years ago
Pls help me with this problem!!
Olenka [21]

Answer:

v = 19.6 m/s.

Explanation:

Given that,

The radius of the circle, r = 5 m

The time period of the ball, T = 1.6s

We need to find the ball's tangential velocity.

The formula for the tangential velocity is given by :

v=\dfrac{2\pi r}{T}

Putting all the values in the above formula

v=\dfrac{2\pi \times 5}{1.6}\\\\v=19.6\ m/s

So, the tangential velocity of the ball is 19.6 m/s. Hence, the correct option is (c).

7 0
2 years ago
If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite d
Yuliya22 [10]

Incomplete question as the mass of baseball is missing.I have assume 0.2kg mass of baseball.So complete question is:

A baseball has mass 0.2 kg.If the velocity of a pitched ball has a magnitude of 44.5 m/sm/s and the batted ball's velocity is 55.5 m/sm/s in the opposite direction, find the magnitude of the change in momentum of the ball and of the impulse applied to it by the bat.

Answer:

ΔP=20 kg.m/s

Explanation:

Given data

Mass m=0.2 kg

Initial speed Vi=-44.5m/s

Final speed Vf=55.5 m/s

Required

Change in momentum ΔP

Solution

First we take the batted balls velocity as the final velocity and its direction is the positive direction and we take the pitched balls velocity as the initial velocity and so its direction will be negative direction.So we have:

v_{i}=-44.5m/s\\v_{f}=55.5m/s

Now we need to find the initial momentum

So

P_{1}=m*v_{i}

Substitute the given values

P_{1}=(0.2kg)(-44.5m/s)\\P_{1}=-8.9kg.m/s

Now for final momentum

P_{2}=mv_{f}\\P_{2}=(0.2kg)(55.5m/s)\\P_{2}=11.1kg.m/s

So the change in momentum is given as:

ΔP=P₂-P₁

=[(11.1kg.m/s)-(-8.9kg.m/s)]\\=20kg.m/s

ΔP=20 kg.m/s

3 0
3 years ago
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