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Aleksandr [31]
3 years ago
12

Which countries were considered the three major Axis Powers?

Physics
1 answer:
7nadin3 [17]3 years ago
8 0
B. JAPAN, GERMANY, and ITALY

The main Axis powers were Japan, with Emperor Hirohito as leader; Germany, with Adolf Hitler as leader; and Italy, with Benito Mussolini as leader. They were all dictators.

The Axis powers began to form in 1936

15th October 1936 - Germany and Italy signed a friendship treaty - Rome-German Axis.
25th November 1936 - Germany and Japan signed a treaty against communism - Anti-Comintern Pact

22nd May 1939 - Germany and Italy signed a stronger alliance - Pact of Steel
27th September 1940 - Japan signed the Pact of Steel - It became known as the Tripartite Pact.
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A golf ball has a mass of 120g. Calculate its increase in mass when it is travelling at 40ms1. What is this as a percentage of i
kicyunya [14]

Answer:

Percentage=8.889\times 10^{-13}%

Explanation:

From special theory of relativity the dynamic mass m is related with the rest mass m_{0}of the body as

m=\frac{m_{0} }{\sqrt{1-\frac{v^{2} }{c^{2} } } }

Here, c is the speed of light and v is the velocity of object.

Given mass of the golf ball is 120 g.

m=\frac{120 }{\sqrt{1-\frac{(40)^{2} }{(3\times 10^{8} )^{2} } } }\\m=120(1-\frac{(40)^{2} }{(3\times 10^{8}) ^{2} })^{-\frac{1}{2} } \\

Now applying the binomial theorem and solve the above equation.

m=(1+\frac{1}{2}(\frac{40}{3\times 10^{8} }) ^{2} )\\m=120(1+8.889\times 10^{-15})

Therefore, increase in mass is,

\Delta m=120\times 8.889\times 10^{-15} \\\Delta m=10.6668\times 10^{-13} g

Now percentage of increase in mass with rest mass is,

Percentage=\frac{10.6668\times 10^{-13} g}{120g} \times 100\\Percentage=8.889\times 10^{-13}

Therefore, the percentage of increase in mass with rest mass is Percentage=8.889\times 10^{-13}.

4 0
4 years ago
Two uniform solid cylinders, each rotating about its central (longitudinal) axis, have the same mass of 3.44 kg and rotate with
Free_Kalibri [48]

Answer:

(a) 20,154.1 J

(b) 95,223.5 J

Explanation:

The expression for the moment of inertia for the uniform solid cylinder is as follows;

I= \frac{1}{2}mr^{2}

Here, I is the moment of inertia, r is the radius and m is the mass of the object.

The expression for the rotational kinetic energy is as follows;

K= \frac{1}{2}I\omega ^{2}

Here, K is the rotational kinetic energy and \omega is the angular velocity.

(a)

Calculate the moment of inertia of the smaller solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.356 m.

I= \frac{1}{2}(3.44)(0.356)^{2}

I= 0.218 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 0.218 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(0.218)(430) ^{2}

K= 20,154.1 J

Therefore, the rotational kinetic energy for the smaller cylinder is 20,154.1 J.

(b)

Calculate the moment of inertia of the larger solid cylinder.

I= \frac{1}{2}mr^{2}

Put m= 3.44 kg and r= 0.775 m.

I= \frac{1}{2}(3.44)(0.775)^{2}

I= 1.03 kg m^{2}

Calculate the rotational kinetic energy of the smaller cylinder.

K= \frac{1}{2}I\omega ^{2}

Put I= 1.03 kg m^{2} and \omega = 430 rads^{-1}.

K= \frac{1}{2}(1.03)(430) ^{2}

K= 95,223.5 J

Therefore, the rotational kinetic energy for the larger cylinder is 95,223.5 J.

7 0
4 years ago
What is the relationship between the frequency and the pitch of a sound?
jarptica [38.1K]
The pitch of a sound come from the frequency of the soundwave, soundwaves that have bigger frequencies sound with a high pitch and soundwaves with less frequencie have low pitch.
6 0
3 years ago
The density of sodium is 968 g/cm3. Suppose you need 250 gm of sodium for an experiment. Which volume of sodium do you need?
Tatiana [17]
We know, d = m/v
d = 968 g/cm3
m = 250 gm

Substitute their values, 
968 = 250 / v
v = 250 / 968
v = 0.26 cm3

In short, Your Answer would be Option B

Hope this helps!
8 0
3 years ago
Plzzzz helpppppppo Near the end of the life cycle of a star why does the star lose its size
gavmur [86]

Answer:

Because the energy is waning

Explanation: hope this helps

8 0
3 years ago
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