The distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
<h3>What is concave mirror?</h3>
A concave mirror has a reflective surface that is curved inward and away from the light source.
Concave mirrors reflect light inward to one focal point and it usually form real and virtual images.
<h3>
Object distance of the concave mirror</h3>
Apply mirrors formula as shown below;
1/f = 1/v + 1/u
where;
- f is the focal length of the mirror
- v is the object distance
- u is the image distance
when image height = object height, magnification = 1
u/v = 1
v = u
Substitute the given parameters and solve for the distance of the object from the mirror's vertex
1/f = 1/v + 1/v
1/f = 2/v
v = 2f
v = 2(19.5 cm)
v = 39 cm
Thus, the distance of an object from the mirror's vertex if the image is real and has the same height as the object is 39 cm.
Learn more about concave mirror here: brainly.com/question/27841226
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Answer: 12,600,000Cm
Explanation:
From the data's;
Charges(q) = 1.8 PC equal to 1.8 x 10^¹²C
Distance = 7 micrometer, is equal to 0.0000070m
From the equation of electric dipole moment, p= q x d, where q= charge, d=distance and p is the dipole moment.
Then we have 1.8x10^¹² x 0.0000070= 12,600,000Cm
NB: The charges are identical.
Answer: <em>Powdered sugar</em>
Powdered sugar dissolves faster compare to the sugar cube. Because sugar cube has less surface area (the granules are tightly packed) compared to powdered sugar
They share covalent bonds
Answer:
These molecules push the layer of molecules down / near, so they also start to vibrate. In this way, the oscillation is followed by one molecule next to it.
