The box has volume
11 in × 3 in × <em>x</em> in = 33<em>x</em> in³
and surface area
2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²
The volume and area have the same value if
33<em>x</em> = 66 + 28<em>x</em>
Solve this equation for <em>x</em> :
33<em>x</em> - 28<em>x</em> = 66
5<em>x</em> = 66
<em>x</em> = 66/5 = 13.2
Oui oui klasa 4 storadjen jsai
15/4 - 6/5 , 300/20 -24/20, 276/20, 69/5
Answer:
a² + 4 a + 4
Step-by-step explanation:
( a + 2 ) ( a + 2 )
Expand brackets
a² + 2 a + 2 a + 4
Simplify
a² + 4 a + 4
