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lawyer [7]
3 years ago
6

In 1993, the sports league introduced a salary cap that limits the amount of money spent on players' salaries. The quadratic mod

el y =0.2313x^2+2.600x+35.17 approximates this cap in millions of dollars for the years 1992​-2008​, where x=0 represents 1992​, x=1 represents 1993​, and so on. The approximate sports league salary cap in 2004 is $99.7 million.
Required:
In what year did the salary cap reach 65 million dollars?
Mathematics
1 answer:
jeyben [28]3 years ago
8 0

Answer:

1999

Step-by-step explanation:

y  = 0.2313(y - 1992)^2 + 2.600(y - 1992) + 35.17

verify with known data point

y  = 0.2313(2004 - 1992)^2 + 2.600(2004 - 1992) + 35.17

y  = 0.2313(12)^2 + 2.600(12) + 35.17

y  = 27.9873 + 28.6 + 35.17

y = 99.6772  which verifies our equation

65 = 0.2313x² + 2.6x + 35.17

 0 = 0.2313x² + 2.6x - 29.83

quadratic formula

x = (-2.6 ±√(2.6² - 4(0.2313)(-29.83))) / (2(0.2313))

x = (-2.6 + 5.86) / 0.4626 = 7.05 years

7.05 = y - 1992

y = 1999.05

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The sum of two numbers is 50 and the difference is 10. What are the numbers?
Black_prince [1.1K]

Answer:

I believe the answer is 20 and 30

5 0
3 years ago
For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of
Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is (-1)^{k+1}(\frac{1}{2^{k}}).

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as (-1)^{k+1}(\frac{1}{2^{k}}).

where k is from 1 to 10.

By the given expression sequence will be \frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......

In this sequence first term "a" = \frac{1}{2}

and common ratio in each successive term to the previous term is 'r' = \frac{\frac{(-1)}{4}}{\frac{1}{2} }

r = -\frac{1}{2}

Since the sequence is infinite and the formula to calculate the sum is represented by

S=\frac{a}{1-r} [Here r is less than 1]

S=\frac{\frac{1}{2} }{1+\frac{1}{2}}

S=\frac{\frac{1}{2}}{\frac{3}{2} }

S = \frac{1}{3}

Now we are sure that the sum of infinite terms is \frac{1}{3}.

Therefore, sum of 10 terms will not exceed \frac{1}{3}

Now sum of first two terms = \frac{1}{2}-\frac{1}{4}=\frac{1}{4}

Now we are sure that sum of first 10 terms lie between \frac{1}{4} and \frac{1}{3}

Since \frac{1}{2}>\frac{1}{3}

Therefore, Sum of first 10 terms will lie between \frac{1}{4} and \frac{1}{2}.

Option D will be the answer.

3 0
3 years ago
Neeeeeeeeed your help
Over [174]

Answer:

9/15=3/5

so 3/5 is equivalent fraction of the 9/15

4 0
3 years ago
Read 2 more answers
Pls help
Karolina [17]

Answer:

D

Step-by-step explanation:

If we look at the right side of the equation we see that the y-intercept is 2, so we will place a point on (0,2).

Next, we look to see if the slope of the graph if positive or negetive, and to see what is the slope (2x).

Finally, we look at the inequality if it is greater than (>), less than (<), greater than or equal to (_>), or less than or equal to (<_).

*Note the following:

if < then the line is dotted and the shading will be under the line.

if > then the line is dotted and the shading will be above the line.

if <_ then the line is solid and the shading will be under the line.

if _> then the line is solid and the shading will be above the line.*

It is a lot of information if you look at it, but with practice it can be made easier.

8 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

b^2 - 4ac

The solution contains the term \sqrt{b^2 - 4ac} which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation 2x^2 - 7x - 9

b^2 - 4ac

= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121

This equation has two real number solutions.

For the quadratic equation 4x^ 2 - 3x- 1

b^2 - 4ac

= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

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