Can someone please help me on exercise 1.6, #2 (a to e). *Will report any spam answers* Thank you!
1 answer:
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Answer:
Area = 2500 square feet is the largest area enclosed
Step-by-step explanation:
A rectangular piece of land borders a wall. The land is to be enclosed and to be into divided 3 equal plots with 200 feet of fencing
Let x be the length of each box and y be the width of the box
Perimeter of the box= 3(length ) + 4(width)
solve for y
divide both sides by 4
Area of the rectangle = length times width
Now take derivative
Set it =0 and solve for x
multiply both sides by 2/9
For any value of x, second derivative is negative
So maximum at x= 100/3
, replace the value of x
Area = 2500 square feet is the largest area enclosed